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matrenka [14]
3 years ago
9

Which expression represents the correct form for the quotient and remainder, written as partial fractions, of

Mathematics
1 answer:
Oduvanchick [21]3 years ago
8 0

Answer:

  • C)~A+ \frac{B}{x-3} +\frac{c}{(x-3)^2}

Step-by-step explanation:

→ \frac{(7x^2-40x+52)}{(x^2-6x+9)}

→ \frac{7x^2-40x+52}{x^2-2.3x+(3)^2}

→  \frac{7x^2-40x+52}{(x-3)^2}

<u>So, your answer is C</u>

<u></u>----------<u></u>

<u>hope it helps...</u>

<u>have a great day!!</u>

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Find x please!!<br> a.10<br> b.32<br> c.116<br> d.16
AysviL [449]

9514 1404 393

Answer:

  (d)  16

Step-by-step explanation:

Angles opposite sides of the same measure are congruent. Here, the triangle is isosceles, so the base angles are congruent:

  2x = 32

  x = 16 . . . . . . divide by 2°

5 0
3 years ago
Which dimensions can create more than one triangle? A. Three angles measuring 75°,45°, and 60°. B. 3 sides measuring 7, 10, 12?
NeTakaya

This is vague.  Any dimensions that make a triangle can make more than one, just draw another right next to it.  What's really being asked is which dimensions can make more than one non-congruent triangle.

<span>A. Three angles measuring 75°,45°, and 60°.

That's three angles, and 75+45+60 = 180, so it's a legit triangle. The angles don't determine the sides, so we have whole family of similar triangles with these dimensions.  TRUE

<span>B. 3 sides measuring 7, 10, 12?

</span>Three sides determine the triangles size and shape uniquely; FALSE

<em>C. Three angles measuring 40</em></span><span><em>°</em></span><em>, 50°</em><span><em>, and 60°? </em>

40+50+60=150, no such triangle exists.  FALSE

<em>D. 3 sides measuring 3,4,and 5</em>

Again, three sides uniquely determine a triangle's size and shape;  FALSE


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7 0
3 years ago
Read 2 more answers
Enter your answer and show all the steps that you use to solve this problem in the space provided.
rodikova [14]

Answer:

\boxed{f(x) - g(x) = 2x(2x^{2} + x + 1)}

Step-by-step explanation:

f(x) = 9x³ + 2x² - 5x + 4; g(x)=5x³ -7x + 4

Step 1. Calculate the difference between the functions

(a) Write the two functions, one above the other, in decreasing order of exponents.

ƒ(x) = 9x³ + 2x² - 5x + 4

g(x) = 5x³           - 7x + 4

(b) Create a subtraction problem using the two functions

        ƒ(x) =    9x³ + 2x² - 5x + 4

      -g(x) =  <u>-(5x³           - 7x + 4) </u>

ƒ(x) -g(x)=

(c). Subtract terms with the same exponent of x

        ƒ(x)   =    9x³ + 2x² - 5x + 4

      -g(x)  =   <u>-(5x³          -  7x + 4) </u>

ƒ(x) -g(x) =      4x³ + 2x² + 2x

Step 2. Factor the expression

y = 4x³ + 2x² + 2x

Factor 2x from each term

y = 2x(2x² + x + 1)

\boxed{f(x) - g(x) = 2x(2x^{2} + x + 1)}

5 0
3 years ago
What is 0.8 as a fraction???? Plz answer is u r right I’ll give u brainliest!!!!
const2013 [10]
<h2>\red { \orange {\boxed {\boxed{Answer}}}}</h2><h2>= 0.8</h2><h2>=  \frac{8}{10}</h2><h2>=  \frac{8 \div 2}{10 \div 2}</h2><h2>=  \frac{4}{5}</h2>

#IfWrongPleaseReport

#StudyTogetherWithMe

#ILoveMath

8 0
3 years ago
Read 2 more answers
1. Considere as funções f e g, ambas com domínio Z, dadas por f(x) = x²- 2x e g(x) = x³-1. Associe as colunas e assinale a alter
Greeley [361]

Answer:

(A)C,D,A,B

Step-by-step explanation:

f(x) = x^2- 2x\\g(x) = x^3-1

a)

f(-2) = (-2)^2- 2(-2)\\=4-(-4)\\=4+4\\=8$ (C)

b)

g(-2) = (-2)^3-1\\\=-8-1\\=-9 $(D)

c)

f(-1) = (-1)^2- 2(-1)=1+2=3\\g(3) = (3)^3-1=27-1=26\\f(-1) + g(3)=3+26\\=29$ (A)

d) f(5) : g(2)

f(5) = (5)^2- 2(5)=25-10=15\\g(2) = (2)^3-1=8-1=7\\f(5) :g(2)=15/7$ (B)

5 0
3 years ago
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