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agasfer [191]
3 years ago
9

When does differentiation begin in a human embryo? day 4-5 day 10 day 25-26 day 50

Biology
2 answers:
horsena [70]3 years ago
7 0

Answer:

Option). 4-5 days.

Explanation:

Morula is a 4-5 days stage of early embryonic development. It represents a solid ball, having 16 cells, known as blastomeres. In human embryo, differentiation begins with morula stage, along with cleavage to form trophoblast (an outer layers of cell) and inner cell mass.

During development, trophoblast forms embryonic part of placenta and inner cell mass form respective structures of embryo.

Thus, the correct answer is option).4-5 days.

Butoxors [25]3 years ago
7 0

Answer:

Day 4-5

Explanation:

The first cell differentiation occurs when the embryo reaches approximately five days after fertilization, forming the blastocyst.

In this case, the cells on the outside undergo the process of <u>differentiation</u> and become responsible for the formation of embryonic attachments (structures that derive from the embryo's germ leaflets but are not part of the embryo's body, such as the amnion).

In the meantime, those cells that remained inside, also undergoing the process of differentiation, become pluripotent stem cells, which are responsible and capable of forming all tissues.

Previously, when they are still undergoing the process of dividing up to 8 cells, each cell is capable of forming a complete being when inserted into an egg.

By going through the whole process and becoming pluripotent stem cells, they can form all kinds of body tissues, but no longer a complete being.

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Answer:

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Explanation:

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3 years ago
1. In a population of 200 field mice, 98 mice are homozygous dominant for brown fur (FF), 84 mice are heterozygous (Ff), and 18
iVinArrow [24]
A.
The genotype frequencies can be determined by dividing the number of individuals with a genotype by the total number all the individuals. 
FF genotype frequency:
98÷200=0,49. There are approximately 5 <span>homozygous dominant mice in 10.
Ff genotype frequency:
84</span>÷200=0,42. There are approximately 4 <span>heterozygous mice in 10.
ff genotype frequency:
18</span>÷200=0,09. There are approximately 1 <span>homozygous recessive mouse in 10.

B.
To determine the frequency of an allele we can divide the number of times that the allele appears by the total number of alleles.
F allele frequency:
</span>\frac{(98*2)+84}{400}<span>=0.7
There are 7 F alleles in 10 random alleles.
f </span>allele frequency:
\frac{84+(18*2)}{400}=0.3
There are 3 f alleles in 10 random alleles.<span>
</span>
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4 years ago
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devlian [24]

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Explanation:

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