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kakasveta [241]

3 years ago

11

A line has a slope of -3 and y-intercept of 5. write the equation of the line in slope intercept. form and explain how you would

use the slope and y-intercept to graph the equation.

1 answer:

mamaluj [8]3 years ago

3 0

Equation: y= mx + b

y = -3x +5

Graph the y intercept first.

Go down three times on the y axis.

Go across one because of -3/1 .

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What is the missing number? 7/18 21/?

Taya2010 [7]

Answer:

d

Step-by-step explanation:

7x3=21

18x3=54

7 0

3 years ago

Read 2 more answers

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Setler79 [48]

Answer:

graph 1 = greater than 1

graph 2 = 0

graph 3 = 0

graph 4 = less than 0

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3 years ago

10y - 3y = 15 graph using the table of values

harina [27]

Answer:

y+15/7

Step-by-step explanation:

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6 0

3 years ago

Determine if the events A and B are independent. Show all steps.

zmey [24]

<u><em></em></u>

Answer:

$P(A U B ) = \frac{13}{25}$

Step-by-step explanation:

<u><em>STEP:-1</em></u>

Given that events A and B are independent then

P(A ∩B ) = P(A) P(B)

Given that P(A) = 2/5 and P(B) = 1/5

<u><em>STEP:- 2</em></u>

P(A ∩B ) = P(A) P(B)

$P(A U B) = P(A) +P(B) - P(A n B )$

$P(A U B ) = P(A) +P(B) - P(A) P(B)$

<u><em>Step(iii):-</em></u>

<u><em></em></u> $P(A U B ) = \frac{2}{5} +\frac{1}{5} - \frac{2}{5} X \frac{1}{5}$ <u><em></em></u>

<u><em></em></u> $P(A U B ) = \frac{3}{5} - \frac{2}{5} X \frac{1}{5}$ <u><em></em></u>

<u><em></em></u> $P(A U B ) = \frac{3}{5} - \frac{2}{25}$ <u><em></em></u>

<u><em></em></u> $P(A U B ) = \frac{15-2}{25} = \frac{13}{25}$ <u><em></em></u>

<u><em /></u>

<u><em /></u>

4 0

3 years ago

Write a polynomial function of minimum degree in standard form with real coefficients whose zeros and their multiplicities inclu

Softa [21]

<u>Answer-</u>

<em>The polynomial function is,</em>

$y=x^4-10x^3+38x^2-64x+40$

<u>Solution-</u>

The zeros of the polynomial are 2 and (3+i). Root 2 has multiplicity of 2 and (3+i) has multiplicity of 1

The general form of the equation will be,

$\Rightarrow y=(x-(2))^2(x-(3+i))(x-(3-i))$ ( ∵ (3-i) is the conjugate of (3+i) )

$\Rightarrow y=(x-2)^2(x-3-i)(x-3+i)$

$\Rightarrow y=(x^2-4x+4)((x-3)-i)((x-3)+i)$

$\Rightarrow y=(x^2-4x+4)((x-3)^2-i^2)$

$\Rightarrow y=(x^2-4x+4)((x^2-6x+9)+1)$

$\Rightarrow y=(x^2-4x+4)(x^2-6x+10)$

$\Rightarrow y=x^2x^2-6x^2x+10x^2-4x^2x+4\cdot \:6xx-4\cdot \:10x+4x^2-4\cdot \:6x+4\cdot \:10$

$\Rightarrow y=x^4-10x^3+14x^2+24x^2-40x-24x+40$

$\Rightarrow y=x^4-10x^3+38x^2-64x+40$

Therefore, this is the required polynomial function.

4 0

3 years ago