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GalinKa [24]
2 years ago
9

Please help me ASAP!!!!!

Mathematics
2 answers:
sergey [27]2 years ago
4 0

Answer:

c and b

Step-by-step explanation:

behdjdurjnrnrjdjdjdi

posledela2 years ago
3 0
C and b look pretty similar
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What is the midpoint of the line segment with endpoints
sertanlavr [38]

Answer:

Midpoint

Step-by-step explanation:

The midpoint is the point on the segment halfway between the endpoints. It may be the case that the midpoint of a segment can be found simply by counting. If the segment is horizontal or vertical, you can find the midpoint by dividing the length of the segment by 2 and counting that value from either of the endpoints.

3 0
3 years ago
Someone please help! Here's the question: Twenty boys signed up for the school play. The number of girls who signed up was 195%
kipiarov [429]
20*1.95 =39 girls
26girls/39girls =0.667
0.667*100 = 66.67%
8 0
4 years ago
What is 271,403 rounded to the nearest hundred thousand .
MAXImum [283]

271,403.00000

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
A raffle offers one $8000.00 prize, one $4000.00 prize, and five $1600.00 prizes. There are 5000 tickets sold at $5 each. Find t
Harman [31]

Answer:

The expectation is  E(1 )= -\$ 1

Step-by-step explanation:

From the question we are told that  

     The first offer is  x_1 =  \$ 8000

     The second offer is  x_2 =  \$ 4000

      The third offer is  \$ 1600

      The number of tickets is  n  =  5000

      The  price of each ticket is  p= \$ 5

Generally expectation is mathematically represented as

             E(x)=\sum  x *  P(X = x )

     P(X =  x_1  ) =  \frac{1}{5000}    given that they just offer one

    P(X =  x_1  ) = 0.0002    

 Now  

     P(X =  x_2  ) =  \frac{1}{5000}    given that they just offer one

     P(X =  x_2  ) = 0.0002    

 Now  

      P(X =  x_3  ) =  \frac{5}{5000}    given that they offer five

       P(X =  x_3  ) = 0.001

Hence the  expectation is evaluated as

       E(x)=8000 *  0.0002 + 4000 *  0.0002 + 1600 * 0.001

      E(x)=\$ 4

Now given that the price for a ticket is  \$ 5

The actual expectation when price of ticket has been removed is

      E(1 )= 4- 5

      E(1 )= -\$ 1

4 0
3 years ago
How can i solve 2×2+16x+y+34=0
IRISSAK [1]
PEMDAS
multiply 2x2=4 and simplify the equation by looking for like terms to combine.

4+16x+y+34=0

4 and 34 are like terms so add them. 
the simplified expression is 16x+y+38




6 0
3 years ago
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