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PtichkaEL [24]
3 years ago
14

A kilobyte is 210 bytes and a megabyte is 220 bytes. How many kilobytes are in a megabyte?

Mathematics
1 answer:
Dmitrij [34]3 years ago
8 0

Answer:

Around 1.04. Exactly 1.047619048

Step-by-step explanation:

Please mark me brainliest. I have never been marked brainliest before.

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The mean age of Lincoln's tee-ball team is 5. Suppose one of his 7-year-old teammates quits the team, but a 6-year-old joins the
aleksandrvk [35]

Answer:

Depending on the amount of children in the tee ball team, the mean may be lowered drastically or minorly. However, the mean would no longer be 5, although it may round up to five, if it is a decimal.

Step-by-step explanation:

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6 0
3 years ago
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What property is 5+0=n
andre [41]

Assuming that you mean to put n instead of 5, this is demonstrating The Identity Property.


The identity property is the property that states that by adding 0 to a number, you don't change the value. For example, 510 + 0 = 510.

4 0
3 years ago
Jorge is asked to build a box in the shape of a rectangular prism. The maximum girth of the box is 20 cm. What is the width of t
MariettaO [177]

Answer:

The width of the box is 6.7 cm

The maximum volume is 148.1 cm³

Step-by-step explanation:

The given parameters of the box Jorge is asked to build are;

The maximum girth of the box = 20 cm

The nature of the sides of the box = 2 square sides and 4 rectangular sides

The side length of square side of the box = w

The length of the rectangular side of the box = l

Therefore, we have;

The girth = 2·w + 2·l = 20 cm

∴ w + l = 20/2 = 10

w + l = 10

l = 10 - w

The volume of the box, V = Area of square side × Length of rectangular side

∴ V = w × w × l = w × w × (10 - w)

V = 10·w² - w³

At the maximum volume, we have;

dV/dw = d(10·w² - w³)/dw = 0

∴ d(10·w² - w³)/dw = 2×10·w - 3·w² = 0

2×10·w - 3·w² = 20·w - 3·w² = 0

20·w - 3·w² = 0 at the maximum volume

w·(20 - 3·w) = 0

∴ w = 0 or w = 20/3 = 6.\overline 6

Given that 6.\overline 6 > 0, we have;

At the maximum volume, the width of the block, w = 6.\overline 6 cm ≈ 6.7 cm

The maximum volume, V_{max}, is therefore given when w = 6.\overline 6 cm = 20/3 cm  as follows;

V = 10·w² - w³

V_{max} = 10·(20/3)² - (20/3)³ = 4000/27 = 148.\overline {148}

The maximum volume, V_{max} = 148.\overline {148} cm³ ≈ 148.1 cm³

Using a graphing calculator, also, we have by finding the extremum of the function V = 10·w² - w³, the coordinate of the maximum point is (20/3, 4000/27)

The width of the box is;

6.7 cm

The maximum volume is;

148.1 cm³

5 0
3 years ago
Solve x/10 = -7 A. x = 3 B. x = -0.7 C. x = -17 D. x = -70
timofeeve [1]

Answer:

x = -70

Step-by-step explanation:

x/10 = -7

Multiply each side by 10

x/10*10 = -7*10

x = -70

7 0
3 years ago
To​ ​ get​ ​ an​ ​ accurate​ ​ result,​ ​ a​ ​ sample​ ​ size​ ​ must​ ​ be
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At least 30 ..................
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