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4 years ago

Solve the equation for h. S = l w + w h + h l

Mathematics

1 answer:

____ [38]4 years ago

5 0

Answer:

Check this out..

Step-by-step explanation:

I think I just answered your question

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Solve for x 2x/3 +1 =3

Bess [88]

Answer:

x=3

Step-by-step explanation:

Hello,

The first thing you do is set up your equation, and we are solving for x so we are going to get x by itself on one side of the = sign.

2x/3+1=3 First thing: subtract 1 from BOTH sides.

-1 -1

----------------------

2x/3=2 Multipliy by 3 on both sides

*3 *3

-----------------------

2x=6 Divide by 2 on both sides

/2 /2

-----------------------

x=3

I hope this helped you!!!

5 0

3 years ago

1. Which situation is best described by the

liberstina [14]

Answer:

Step-by-step explanation:

3 0

3 years ago

Mrs.sipp has 4.6 l of lemonade to serve her son's birthday guests. About how many millimeters should she pour into each glass?

vlabodo [156]

1 litre = 1000 ml
4.6 litre = 4600 ml

4600 / people = how much she should pour into each glass

5 0

3 years ago

1. Quadrilateral ABCD has vertices A(-1, 1), B(2, 3), C(6, 0) and D(3, -2). Determine using coordinate geometry whether or not t

deff fn [24]

Answer:

The Conclusion is

Diagonals AC and BD,

a. Bisect each other

b. Not Congruent

c. Not Perpendicular

Step-by-step explanation:

Given:

[]ABCD is Quadrilateral having Vertices as

A(-1, 1),

B(2, 3),

C(6, 0) and

D(3, -2).

So the Diagonal are AC and BD

To Check

The diagonals AC and BD

a. Bisect each other. B. Are congruent. C. Are perpendicular.

Solution:

For a. Bisect each other

We will use Mid Point Formula,

If The mid point of diagonals AC and BD are Same Then

Diagonal, Bisect each other,

For mid point of AC

$Mid\ point(AC)=(\dfrac{x_{1}+x_{2} }{2},\dfrac{y_{1}+y_{2} }{2})$

Substituting the coordinates of A and C we get

$Mid\ point(AC)=(\dfrac{-1+6}{2},\dfrac{1+0}{2})=(\dfrac{5}{2},\dfrac{1}{2})$

Similarly, For mid point of BD

Substituting the coordinates of B and D we get

$Mid\ point(BD)=(\dfrac{2+3}{2},\dfrac{3-2}{2})=(\dfrac{5}{2},\dfrac{1}{2})$

Therefore The Mid point of diagonals AC and BD are Same

Hence Diagonals,

a. Bisect each other

B. Are congruent

For Diagonals to be Congruent We use Distance Formula

For Diagonal AC

$l(AC) = \sqrt{((x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2} )}$

Substituting A and C we get

$l(AC) = \sqrt{((6-(-1))^{2}+(0-1)^{2} )}=\sqrt{(49+1)}=\sqrt{50}$

Similarly ,For Diagonal BD

Substituting Band D we get

$l(BD) = \sqrt{((3-2))^{2}+(-2-3)^{2} )}=\sqrt{(1+25)}=\sqrt{26}$

Therefore Diagonals Not Congruent

For C. Are perpendicular.

For Diagonals to be perpendicular we need to have the Product of slopes must be - 1

For Slope we have

$Slope(AC)=\dfrac{y_{2}-y_{1} }{x_{2}-x_{1} }$

Substituting A and C we get

$Slope(AC)=\dfrac{0-1}{6--1}\\\\Slope(AC)=\dfrac{-1}{7}$

Similarly, for BD we have

$Slope(BD)=\dfrac{-2-3}{3-2}\\\\Slope(BD)=\dfrac{-5}{1}$

The Product of slope is not -1

Hence Diagonals are Not Perpendicular.

6 0

4 years ago

Is 7.8 equal to nine<br>

Butoxors [25]

Answer:

Step-by-step explanation:

7.8 is 7.8 not 9 they are both rational numbers

3 0

4 years ago

Read 2 more answers