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irga5000 [103]
3 years ago
5

(25 POINTS) PLEASE HELP WILL GIVE BRAINLIEST, THANKS AND 5 STAR RATING!!! 5 QUESTIONS SHOW WORK!

Mathematics
1 answer:
marysya [2.9K]3 years ago
8 0

Answer:

Step-by-step explanation:

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The sum of 9/26 and -4/13 is ____ put the answer or else I WILL REPORT YOU
Colt1911 [192]

Answer:

1/26

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Can someone please help me??
dmitriy555 [2]

Answer:

I is clear that, the linear equation 5x+12=5x-7 has no solution.

Step-by-step explanation:

<u>Checking the first option:</u>

\frac{2}{3}\left(9x+6\right)=6x+4

6x+4=6x+4

\mathrm{Subtract\:}4\mathrm{\:from\:both\:sides}

6x+4-4=6x+4-4

6x=6x

\mathrm{Subtract\:}6x\mathrm{\:from\:both\:sides}

6x-6x=6x-6x

0=0

\mathrm{Both\:sides\:are\:equal}

\mathrm{True\:for\:all}\:x

<u>Checking the 2nd option:</u>

5x+12=5x-7

\mathrm{Subtract\:}5x\mathrm{\:from\:both\:sides}

5x+12-5x=5x-7-5x

\mathrm{Simplify}

12=-7

\mathrm{The\:sides\:are\:not\:equal}

\mathrm{No\:Solution}

<u>Checking the 3rd option:</u>

4x+7=3x+7

\mathrm{Subtract\:}7\mathrm{\:from\:both\:sides}

4x+7-7=3x+7-7

\mathrm{Simplify}

4x=3x

\mathrm{Subtract\:}3x\mathrm{\:from\:both\:sides}

4x-3x=3x-3x

\mathrm{Simplify}

x=0

<u>Checking the 4th option:</u>

-3\left(2x-5\right)=15-6x

\mathrm{Subtract\:}15\mathrm{\:from\:both\:sides}

-6x+15-15=15-6x-15

\mathrm{Simplify}\

-6x=-6x

\mathrm{Add\:}6x\mathrm{\:to\:both\:sides}

-6x+6x=-6x+6x

\mathrm{Simplify}

\mathrm{Both\:sides\:are\:equal}

\mathrm{True\:for\:all}\:x

Result:

Therefore, from the above calculations it is clear that, the linear equation

5x+12=5x-7 has no solution.

4 0
3 years ago
John and O’Neill are playing a boardgame in which they roll to number cubes. John needs to get some of a on the number cubes to
Pani-rosa [81]

Answer: John is most likely to win.

Step-by-step explanation: John is most likely to win because he can roll the following numbers:

2,6

3,5

4,4

5,3

6,2

Oh Neil Can only roll these numbers

5,6

6,5

So John would most Likely win

6 0
3 years ago
Find the oth term of the geometric sequence 7, 14, 28, ...
yaroslaw [1]

Answer:

The nth term of the geometric sequence 7, 14, 28, ... is:

a_n=7\cdot \:2^{n-1}

Step-by-step explanation:

Given the geometric sequence

7, 14, 28, ...

We know that a geometric sequence has a constant ratio 'r' and is defined by

a_n=a_1\cdot r^{n-1}

where a₁ is the first term and r is the common ratio

Computing the ratios of all the adjacent terms

\frac{14}{7}=2,\:\quad \frac{28}{14}=2

The ratio of all the adjacent terms is the same and equal to

r=2

now substituting r = 2 and a₁ = 7 in the nth term

a_n=a_1\cdot r^{n-1}

a_n=7\cdot \:2^{n-1}

Therefore, the nth term of the geometric sequence 7, 14, 28, ... is:

a_n=7\cdot \:2^{n-1}

6 0
2 years ago
15 POINTS!!!!
olganol [36]

p/5 + 6 = 10

=> p/5 = 10-6

=> p/5 = 4

=> p = 5×4

=> p = 20

C. 20

4 0
3 years ago
Read 2 more answers
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