WILL MARK BRAINLISET!!!!!!! −3 |x| +2x−1 if x=−5

Mathematics

2 answers:

Galina-37 [17]3 years ago

6 0

Answer:

Substitute the value of the variable into the equation and simplify.

−

-26

Step-by-step explanation:

Sindrei [870]3 years ago

3 0

We are given the equation

$-3|x|+2x-1$

We are told that x=-5, so let's substitute that value into the equation:

$=-3|-5|+2x-1$

The absolute value sign $|x|$ means that any positive number will remain positive and any negative number will be changed to positive in these brackets

$-3(5)+2(-5)-1$

Now, simplify

$=-15-10-1$

And simplify again

$\boxed{=-26}$

This is your answer. Let me know if you need any clarifications, thanks!

~ Padoru

You might be interested in

Let the following sample of 8 observations be drawn from a normal population with unknown mean and standard deviation: 22, 18, 1

BigorU [14]

Answer:

a: Sample mean: 20, Sample standard deviation: 1.732

b: 19.13 <µ < 20.87

c: 18.84< µ < 21.16

d: as the confidence level increases, the interval becomes wider

Step-by-step explanation:

a: Sample mean is found by adding up all the individual values of the sample, then dividing by the total number of values in the sample.

Sample standard deviation is the square root of the variance

See the first attached photo for the calculations of these values.

We need to create a 80% confidence interval for the population. Since n < 30, we will use a t-value with degree of freedom of 7 (the degree of freedom is always one less than the sample size.

Look for the column on the t-distribution chart that has "area in two tails" of 0.20 (80%), and row 7 (degree of freedom)

The t-value is 1.415

See the second attached photo for the construction of the confidence interval

We need to create a 90% confidence interval for the population. Since n < 30, we will use a t-value with degree of freedom of 7 (the degree of freedom is always one less than the sample size.

Look for the column on the t-distribution chart that has "area in two tails" of 0.10 (90%), and row 7 (degree of freedom)

The t-value is 1.895

See the third attached photo for the construction of the confidence interval