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FrozenT [24]
3 years ago
11

How do you write 10,000 in scientific notation?

Mathematics
1 answer:
CaHeK987 [17]3 years ago
5 0
Count up all digits besides the first digit and that's was goes next to the little carrot (^) then if the other digits aren't zero (you include all sandwiched zeros though ex. 4609) you place all of them to the right of the decimal you then place the first digit the one you excluded when counting to the left of the decimal there should only ever be one digit there! The base for this equation is Yx10^z Y times 10 the z power Answer.) 1.0x10^4
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Find x? Please can you help me explain. <br><br> Thank you
VikaD [51]

Answer:

root3/ root2

Step-by-step explanation:

since this is a special right triangle (45, 45, 90) we can use right triangle rules. Basically, C in my photo is equal to the hypotenuse while A and B are equal to the sides. You can substitute your hypotenuse into the formula I gave you to find x.

B = C / root2

x = root3 / root2

hope this helped a little bit

7 0
3 years ago
The area of a rectangle is represented by the expression 62 – 3x2 + 12x.
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PLEASE PLEASE PLEASE PLEASE PLEASE PLEASE HELP ME!!!!!!!! I HAVE 2 QUESTIONS THATS ALL. I WILL GIVE POINTS, FAN, MEDAL. PLEASE I
babunello [35]
I think it would be a also 
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4 years ago
If A and B are nonzero integers with the same signs is the product negative or postitive
melisa1 [442]
Remember.

positive number x positive number = positive number
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3 0
3 years ago
g A milling process has an upper specification of 1.68 millimeters and a lower specification of 1.52 millimeters. A sample of pa
adoni [48]

Complete Question

A milling process has an upper specification of 1.68 millimeters and a lower specification of 1.52 millimeters. A sample of parts had a mean of 1.6 millimeters with a standard deviation of 0.03 millimeters. what standard deviation will be needed to achieve a process capability index f 2.0?

Answer:

The value required is  \sigma =  0.0133

Step-by-step explanation:

From the question we are told that

   The upper specification is  USL  =  1.68 \ mm

    The lower specification is  LSL  = 1.52  \  mm

     The sample mean is  \mu =  1.6 \  mm

     The standard deviation is  \sigma =  0.03 \ mm

Generally the capability index in mathematically represented as

             Cpk  =  min[ \frac{USL -  \mu }{ 3 *  \sigma }  ,  \frac{\mu - LSL }{ 3 *  \sigma } ]

Now what min means is that the value of  CPk is the minimum between the value is the bracket

          substituting value given in the question

           Cpk  =  min[ \frac{1.68 -  1.6 }{ 3 *  0.03 }  ,  \frac{1.60 -  1.52 }{ 3 *  0.03} ]

=>      Cpk  =  min[ 0.88 , 0.88  ]

So

         Cpk  = 0.88

Now from the question we are asked to evaluated the value of  standard deviation that will produce a  capability index of 2

Now let assuming that

         \frac{\mu - LSL  }{ 3 *  \sigma } =  2

So

         \frac{ 1.60 -  1.52  }{ 3 *  \sigma } =  2

=>    0.08 = 6 \sigma

=>     \sigma =  0.0133

So

        \frac{ 1.68  - 1.60 }{ 3 *  0.0133 }

=>      2

Hence

      Cpk  =  min[ 2, 2 ]

So

    Cpk  = 2

So    \sigma =  0.0133 is  the value of standard deviation required

3 0
3 years ago
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