Answer:
In a bumper-to-bumper traffic, when the engine starts overheating the situation can be handled by tapping the accelator which will revive the engine.
Explanation:
Overheating of engine can be due to many reasons. But one should know what to do when an engine overheats in a traffic. Bumper-to-bumper traffic is when the cars are so close in traffic that they touch each other. This usually happens when there's a traffic for a long time or on very busy lane. During summer times, it is important to keep checking the engine temperature to avoid any problem.
When one is stuck in bumper-to-bumper traffic with overheating engine, then there are some meausres that one can take. They are:
- To put the car on park or neutral mode of driving and tap the accelator which will revive the engine.
- The heat can be disperse by rolling down the window and turn the heater up. It will disperse the heat.
Answer:
def course_grader(student_to_grades, course_prefix):
student_grades = dict()
for key, value in student_to_grades.items():
grade_score = 0
for course,grade in value.items():
if course_prefix == course:
grade_score += grade
student_grades[key] = grade_score / len(value.keys())
return student_grades
Explanation:
The course_grader function is a python program that accepts two arguments, the student dictionary and the course prefix. The function returns a dictionary of the student id as the key and the average grade of the student as the value.
The first e-commerce service would be A)Banking. Hope this helps.
Answer:
Check the explanation
Explanation:
A) Whenever C is sending to D, what other communications are possible?
C’s packet will be seen by A, B and D, but not by E. Thus, D can send to E at the sametime..
B) Whenever B is sending to A, what other communications are likely?
Even though B’s packet will not be seen by D, other nodes, e.g., E, or C, can’t send to D since the packets from these nodes will interfere with the packets from B at A. Therefore, other communications is not likely at the same time.
C) Whenever B is sending to C, what other communications are possible?
B’s packet will be seen by E, A and C, by not by D. therefore, E can send to D at the same point.
1. A. the SQRT is the squareroot. 2. may be C. Today but I've never heard of a function that returns the date!
