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Answer:
The output of the given code as follows:
<u>Output:
</u>
1122
Explanation:
In the given java code the two for loop is defined, which can be described as follows:
- In the first loop, a"loop" variable is used, which starts from 1 and ends when the value of loop is less than 3, inside the loop a print function is used, that print value 1.
- In the next step, another for loop is declared, inside the loop a variable "loop2" variable is used, that's working is the same as the above loop, but in this loop, it will print a value, that is 2.
Answer:
Following are the solution to the given question:
Explanation:
The size of cache memory 
The block size
Therefore, 
are blocks.
The collection consists of 4 blocks. Therefore,
are sets. Because the size of its cache block is 16, the block offset comprises 4 bits. There would be 5 bits inset offset since there are 32 caches. An Address contains 32 bits, while the space of the tags contains 
bits.
It really depends on the amount each is meant to hold (take for example, a flash drive, there are some for only 1 GB, and others that hold 5 GB, and so on).
The smallest one should be compact disk, which could hold up to 700 megabytes.
hope this helps
Answer:
Explanation:
The code provided aside from some minor errors (fixed version down below) is correct, but it will never be able to accomplish what is being asked in the question. This is because this code is simply copying and returning the exact same list that is passed as an argument, because it is looping through it and comparing its own elements. In order to accomplish what is asked in the question, two lists need to be passed as parameters. The first would be the original list, and the second would be a list of test elements that will be used to compare and see if they exist in the original list. This would allow us to create a new list with only the elements that existed in the original list.
def filter_only_strs(lst):
for x in lst:
if not isinstance(x, str):
lst.remove(x)
return lst
