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scoray [572]
3 years ago
9

How much of a 14% solution of iodine should be added to 89 ounces of a 47% iodine solution to get a 29% solution

Mathematics
1 answer:
Andrews [41]3 years ago
3 0
We have 89 ounces of 47% iodine.
We will add "x" ounces of 14% iodine to get a 29% iodine solution.
89 * .47 + .14x = .29 * (89 + x)
41.83 + .14x = 25.81 + .29x
16.02 = .15x
x = 106.80
So, we must add 106.80 ounces of 14% iodine to get a 29% iodine solution.
(for a total of 195.80 ounces)

Source:
http://www.1728.org/mixture.htm


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Answer with Step-by-step explanation:

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224 students out of 560 students chose chocolate ice cream. What percent is this?
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Unknown to a medical researcher, 6 out of 25 patients have a heart problem that will result in death if they receive the test dr
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Using the hypergeometric distribution, it is found that there is a 0.0002 = 0.02% probability that exactly 6 patients will die.

<h3>What is the hypergeometric distribution formula?</h3>

The formula is:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • N is the size of the population.
  • n is the size of the sample.
  • k is the total number of desired outcomes.

The values of the parameters for this problem are:

N = 25, k = 6, n = 8.

The probability that exactly 6 patients will die is P(X = 6), hence:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}

P(X = 6) = h(6,25,8,6) = \frac{C_{6,6}C_{19,2}}{C_{25,8}} = 0.0002

0.0002 = 0.02% probability that exactly 6 patients will die.

More can be learned about the hypergeometric distribution at brainly.com/question/24826394

#SPJ1

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