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scoray [572]
3 years ago
9

How much of a 14% solution of iodine should be added to 89 ounces of a 47% iodine solution to get a 29% solution

Mathematics
1 answer:
Andrews [41]3 years ago
3 0
We have 89 ounces of 47% iodine.
We will add "x" ounces of 14% iodine to get a 29% iodine solution.
89 * .47 + .14x = .29 * (89 + x)
41.83 + .14x = 25.81 + .29x
16.02 = .15x
x = 106.80
So, we must add 106.80 ounces of 14% iodine to get a 29% iodine solution.
(for a total of 195.80 ounces)

Source:
http://www.1728.org/mixture.htm


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Therefore,

\left(g/f\right)\left(x\right)=\frac{x}{4}-\frac{1}{16}-\frac{79}{16\left(4x+1\right)}

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Use the Pythagorean Theorem to solve this problem.

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"c" is the length of the longest side or value, also the hypotenuse.

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Then<u> simplify and  isolate "c" </u>to find the largest value.

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