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Answer:
Step-by-step explanation:
The potential in a region between x = 0 and x = 6.00 m is V = a + bx.
Put a = 15.4 V and b = -5.10 V/m.
So,
To find: Potential at x =0, 3, 6
Solution:
Potential at x = 0:
Potential at x = 3:
Potential at x = 6:
Therefore,
Answer:
0.3333 = 33.33% probability that the employee will arrive between 8:15 a.m. and 8:25 a.m.
Step-by-step explanation:
A distribution is called uniform if each outcome has the same probability of happening.
The uniform distributon has two bounds, a and b, and the probability of finding a value between c and d is given by:
A particular employee arrives at work sometime between 8:00 a.m. and 8:30 a.m.
We can consider 8 am = 0, and 8:30 am = 30, so
Find the probability that the employee will arrive between 8:15 a.m. and 8:25 a.m.
Between 15 and 25, so:
0.3333 = 33.33% probability that the employee will arrive between 8:15 a.m. and 8:25 a.m.