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JulsSmile [24]
3 years ago
5

Please Help. Find the area. Thank you

Mathematics
2 answers:
Andru [333]3 years ago
7 0

Answer:

432 yd squared

Step-by-step explanation:

This is a parallelogram. The area of a parallelogram is denoted by: A = bh, where b is the base and h is the height. Here, the base is b = 19 1/5 and the height is h = 22 1/2. Plug these in:

A = bh = (19 1/5) * (22 1/2)

To make this simpler, let's convert the numbers into decimals. 1/5 is just 0.2 so 19 1/5 is 19.2. 1/2 is just 0.5, so 22 1/2 is 22.5. Now we have:

A = 19.2 * 22.5 = 432

Thus the area is 432 yd squared.

Hope this helps!

ycow [4]3 years ago
6 0

Answer:

Step-by-step explanation:

Area of a parallelogram = base * height

=19 1/5 * 22 1/2

= \frac{96}{5}*\frac{45}{2}\\\\=48*9\\\\=432 square yards

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Answer:

Bernice would need 6 days assuming that everything remains constant to make $2430.

Step-by-step explanation:

Assuming she sells every single seashell every day.

First, find the total amount she makes per day by multiply the amount she sells them for ($3) with the total amount of sea shells she sells each day ($135):

135 x 3 = $405

Bernice makes $405 each day.

Now, to solve for the amount of days, divide the total amount she wants to make ($2430) with the amount she makes per day ($405):

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~

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3 years ago
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Write this as a fraction.

\frac{2}{6}

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3 years ago
An online streaming service providing television programs claims that a 30-minute program will stream with advertisements that a
trapecia [35]

Answer:

The p-value is significantly low(<0.01), which means that the data provides convincing evidence that the true mean advertisement length is longer than 45 seconds.

Step-by-step explanation:

An online streaming service providing television programs claims that a 30-minute program will stream with advertisements that average 45 seconds. Test if the true mean advertisement length is longer than 45 seconds.

At the null hypothesis, we test if the mean time is of 45 seconds, that is:

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At the alternate hypothesis, we test if the mean is more than 45 seconds, that is:

H_1: \mu > 45

The test statistic is:

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, s is the standard deviation and n is the size of the sample.

45 is tested at the null hypothesis:

This means that \mu = 45

They recorded the times of 21 randomly selected advertisements. The mean and standard deviation for these times are 46.67 and 2.78.

This means that n = 21, X = 46.67, s = 2.78

Value of the test-statistic:

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The p-value of the test is the probability of finding a sample mean above 46.67, which is a right-tailed test, with t = 2.75 and 21 - 1 = 20 degrees of freedom.

With the help of a calculator, this p-value is of 0.0062.

The p-value is significantly low(<0.01), which means that the data provides convincing evidence that the true mean advertisement length is longer than 45 seconds.

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