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irakobra [83]
3 years ago
5

Which of the following are necessary when proving that the opposite angles of a parallelogram are congruent? A. Opposite sides a

re perpendicular B. Opposite sides are congruent C. Angle addition postulate D. Segment Addition postulate
Mathematics
2 answers:
Misha Larkins [42]3 years ago
8 0

Answer:

C and B

Step-by-step explanation:

The correct option is option B and C. The necessary condition to prove that the opposite angles of a parallelogram are congruent:

C. Angle Addition Postulate.

B. Opposite sides are congruent

yanalaym [24]3 years ago
3 0

Answer:

The statements that are necessary when proving that the opposite angles of a parallelogram are congruent are:

B. Opposite sides are congruent - This has to be true as opposite sides should be similar.

C. Angle Addition Postulate.  It states that if a point lies on the interior of an angle, that angle is the sum of two smaller angles with legs that go through the given point.

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The shape is a rhombus if and only if the diagonals are perpendicular and the sides are congruent
harina [27]

Answer:

The statement is True

Step-by-step explanation:

Rhombus is a quadrilateral with the following characteristics;

  • All sides are congruent by definition.
  • The diagonals bisect the angles.
  • The diagonals are perpendicular bisectors of each other.
  • Adjacent angles are supplementary.
  • All the four sides are equal.
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3 years ago
Which steps can be used to solve StartFraction 6 Over 7 EndFraction x + one-half = StartFraction 7 Over 8 EndFraction for x? Che
34kurt

Answer:

Subtract One-half from both sides of the equation.

Divide both sides by 6/7

Multiply both sides by 7/6

Step-by-step explanation:

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Sindrei [870]

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3 0
2 years ago
Can you answer this math homework? Please!
luda_lava [24]

Answer: (3.5,-2)

Step-by-step explanation:

To solve this problem, all we have to do is plug in y=-2 into either equations from step one to find the coordinate. To make sure we have the right x-coordinate, let's plug in y for both equations.

4x-7y=28        [plug in y=-2]

4x-7(-2)=28    [multiply]

4x+14=28       [subtract both sides by 14]

4x=14              [divide both sides by 4]

x=3.5

------------------------------------------------------------------------------------------------------------

6x-5y=31        [plug in y=-2]

6x-5(-2)=31    [multiply]

6x+10=31       [subtract both sides by 10]

6x=21             [divide both sides by 6]

x=3.5

Now, we know the solution to the system is (3.5,-2).

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2 years ago
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