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myrzilka [38]
3 years ago
7

Spencer buys 20 strawberries to make smoothies. Each smoothie needs 5 strawberries. Use a count -by to find the number of smooth

ies Spencer can make.
Mathematics
2 answers:
pickupchik [31]3 years ago
6 0
4. because if you divid the 20 by five it is 4
kotykmax [81]3 years ago
4 0

Answer:

4

Step-by-step explanation:

If each smoothies needs 5 strawberries and we have 20 strawberries we can determine the number of smoothies Spencer can make by dividing the number of strawberries that Spencer has and the number of strawberries needed:

=20/5=4

Spencer can make 4 smoothies with 20 strawberries.  

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Please help im really confused :(​
pantera1 [17]

Answer:

a) π

b) 33.4

Step-by-step explanation:

C = πd

1) substitute 105 for C: 105 = πd

2) plug in approximate value of 3.14 for π: 105 = (3.14) d

3) isolate to solve for d: 105/3.14 = d

4) simplify: 105/3.14 ≈ 33.4

5 0
3 years ago
In a race, there are 20 runners. Trophies for the race are awarded to the runners finishing in first and second place. In how ma
andrew11 [14]

Answer:

<u>There are 380 ways that 1st and 2nd place can be determined in the race</u>

Step-by-step explanation:

There are 20 possibilities for determine the 1st place

There are 19 possibilities for determine the 2nd place

Number of ways that 1st and 2nd place can be determined = 20 * 19

Number of ways that 1st and 2nd place can be determined = 380

7 0
3 years ago
Atmospheric pressure decreases by about 11.8% for every 1000 meters you climb. The pressure at sea level is 1013 millibars (a un
erica [24]
At sea level, the pressure is 1013, that's when the altitude is at 0, sea level, let's see

\bf \textit{Periodic Exponential Decay}\\\\&#10;A=I(1 - r)^{\frac{t}{p}}\qquad &#10;\begin{cases}&#10;A=\textit{accumulated amount}\to &1013\\&#10;I=\textit{initial amount}\\&#10;r=rate\to 11.8\%\to \frac{11.8}{100}\to &0.118\\&#10;t=\textit{meters climbed}\to &0\\&#10;p=period\to &1000&#10;\end{cases}&#10;\\\\\\&#10;1013=I(1-0.118)^{\frac{0}{1000}}\implies 1013=I\cdot 1\implies 1013=I

so, the inital amount is 1013, when t = 0,

\bf \textit{Periodic Exponential Decay}\\\\&#10;A=I(1- r)^{\frac{t}{p}}\qquad &#10;\begin{cases}&#10;A=\textit{accumulated amount}\\&#10;I=\textit{initial amount}\to &1013\\&#10;r=rate\to 11.8\%\to \frac{11.8}{100}\to &0.118\\&#10;t=\textit{meters climbed}\to &t\\&#10;p=period\to &1000&#10;\end{cases}&#10;\\\\\\&#10;A=1013(1-0.118)^{\frac{t}{1000}}\implies A=1013(0.882)^{\frac{t}{1000}}

now, to check the atmospheric pressure at 4000, simply set t = 4000, to get A.


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3 years ago
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Here is my expression (7x6) + 12

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