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aleksley [76]
3 years ago
6

What is the slope of the line?​

Mathematics
1 answer:
dsp733 years ago
7 0
<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ Slope = rise/ run

Slope = 4/2

Slope = 2

<h3><u>✽</u></h3>

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

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John and Jane went to a bakery to get cookies for a party. Jane bought x cookies that were $3 each. John bought x cookies that w
Natasha2012 [34]

Answer:

They spent $15.

Step-by-step explanation:

It's given that Jane bought x cookies, so 3x.

John spent $1 on each of the x cookies he got, and also an extra $10, so x+10.

3x=x+10

2x=10

x=5

So they got 5 cookies each.

5 cookies x $3= $15 (check with $5(1)+$10= $5+$10= $15 )

3 0
3 years ago
The scatterplot shows the number of free throws that different basketball players attempted and the number that each player made
Brut [27]
Y= 3x + 7
y= 3x + 5
y= 3x + 6
y= 3x + 3
4 0
3 years ago
1,000,000 divided by 6500 i will mark brainlest
Sveta_85 [38]

Answer:

153.846153846

Step-by-step explanation:

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5 0
3 years ago
A surveyor leaves her base camp and drives 42km on a bearing of 032degree she then drives 28km on a bearing of 154degree,how far
ValentinkaMS [17]

Answer:

The surveyor is 36.076 kilometers far from her camp and her bearing is 16.840° (standard form).

Step-by-step explanation:

The final position of the surveyor is represented by the following vectorial sum:

\vec r = \vec r_{1} + \vec r_{2} + \vec r_{3} (1)

And this formula is expanded by definition of vectors in rectangular and polar form:

(x,y) = r_{1}\cdot (\cos \theta_{1}, \sin \theta_{1}) + r_{2}\cdot (\cos \theta_{2}, \sin \theta_{2}) (1b)

Where:

x, y - Resulting coordinates of the final position of the surveyor with respect to origin, in kilometers.

r_{1}, r_{2} - Length of each vector, in kilometers.

\theta_{1}, \theta_{2} - Bearing of each vector in standard position, in sexagesimal degrees.

If we know that r_{1} = 42\,km, r_{2} = 28\,km, \theta_{1} = 32^{\circ} and \theta_{2} = 154^{\circ}, then the resulting coordinates of the final position of the surveyor is:

(x,y) = (42\,km)\cdot (\cos 32^{\circ}, \sin 32^{\circ}) + (28\,km)\cdot (\cos 154^{\circ}, \sin 154^{\circ})

(x,y) = (35.618, 22.257) + (-25.166, 12.274)\,[km]

(x,y) = (10.452, 34.531)\,[km]

According to this, the resulting vector is locating in the first quadrant. The bearing of the vector is determined by the following definition:

\theta = \tan^{-1} \frac{10.452\,km}{34.531\,km}

\theta \approx 16.840^{\circ}

And the distance from the camp is calculated by the Pythagorean Theorem:

r = \sqrt{(10.452\,km)^{2}+(34.531\,km)^{2}}

r = 36.078\,km

The surveyor is 36.076 kilometers far from her camp and her bearing is 16.840° (standard form).

5 0
3 years ago
How many solutions does the system of nonlinear equations graphed below<br> have?
astra-53 [7]

Answer: Look at the number of points where the graphs intersect each other...the points where the graphs of the functions cross each other are the solutions to the system. 

Upon looking, you should see 4 points where the graphs intersect, so there are 4 solutions to the non-linear system of equations. 

Step-by-step explanation:

7 0
3 years ago
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