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miv72 [106K]
3 years ago
7

A fixed system of charges exerts a force of magnitude 18 n on a 9.0 c charge. the 9.0 c charge is replaced with a 4.0 c charge.

what is the exact magnitude of the force (in n) exerted by the system of charges on the 4.0 c charge? do not include units with your answer.
Physics
1 answer:
laila [671]3 years ago
7 0
According to the law of gravitational force:
the force between any two objects is directly proportional to the masses of the objects and inversely proportional to the square of the distance between these two objects.

Based on this:
if a 9 c charge is replaced with a 4 c charge while the distance between the charges is kept constant:
18/9 = F/4
2 = F/4
F = 2 x 4 = 8
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A small metal sphere has a mass of 0.11 g and a charge of -21.0 nC . It is 10 cm directly above an identical sphere with the sam
GrogVix [38]

Answer:

A. the magnitude of the force between the spheres is 3.97 x 10⁻⁴ N

B. the magnitude of its initial acceleration is 5.83 m/s²

Explanation:

given information:

metal sphere's mass, m = 0.1 g = 1 x 10⁻⁴ kg

charge, q = -21 nC = -2.1 x 10⁻⁸

r = 10 cm = 0.1 m

What is the magnitude of the force between the spheres?

F₁₂ = k q₁q₂/r²

     = ( 9 x 10⁹) (-2.1 x 10⁻⁸)²/(0.1)²

     = 3.97 x 10⁻⁴ N

If the upper sphere is released, it will begin to fall. What is the magnitude of its initial acceleration?

mg - F₁₂ = ma

a = g - (F₁₂/m)

   = 9.8 - (3.97 x 10⁻⁴/1 x 10⁻⁴)

   = 5.83 m/s²

5 0
3 years ago
A 10-μF capacitor in an LC circuit made entirely of superconducting materials ( R = 0 Ω ) is charged to 100 μC. Then a supercond
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Answer:

Vdc=10V

Explanation:

in a closed loop consisting of a super charged capacitor and an inductor, the super charge capacitor acts as a supply when the loop is closed, at t=0, the emf stored in the capacitor is 10V (q/c); and at that same time Vl= voltage across the inductor or loop too would be 10V,

if the loop remains closed for  a longer period, the inductor would absorb energy from the capacitor till it dissipates all charges with itself.

8 0
3 years ago
Ricardo and Jane are standing under a tree in the middle of a pasture. An argument ensues, and they walk away in different direc
Lapatulllka [165]

Answer:

a)     d = 30.79 m , b) θ = -22.4° ,   θ = 22.4 South of East

Explanation:

The easiest way to solve problems with vectors is to use their components, for this the East-West direction coincides with the x-axis and the North-South direction coincides with the y-axis

Let's use the index for / Ricardo and the index for Jane, let's break down the displacements

Richard

X axis

      x₁ = 26.0 sin (60)

      x₁ = -22.52 m

Y Axis  

     y₁ = 26.0 cos 60

     y₁ = 13 m / s

Jane

X axis

       x₂ = 16.0 cos (180 +30)

       x₂ = -13.85 m

Y Axis  

        y₂ = 16.0 sin (180 + 30)

        y₂ = - 8.0 m

Now we can use Pythagoras' theorem to find the distance between them

         d = √ [(x₂ -x₁)² + (y₂ -y₁)²]

         d = √ [(-13.85 + 22.52)² + (-8 -13)²]

         d = 30.79 m

Let's use trigonometry to enter the address

         tan θ = Δy / Δx

         θ = tan⁻¹ Δy / Δx

         θ = tan⁻¹ (-13.85 + 22.52) / (-8 - 13)

         θ = tan⁻¹ (-8.67 / 21)

         θ = -22.4°

The negative sign indicates that the angle is measured from the axis clockwise.

In the form of cardinal s point is

     θ = 22.4 South of East

4 0
4 years ago
Determine the acceleration of the box of mass 140 kg, when a net force of 900 N acts on it.​
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Answer:

a = 6.4 m/s²

Explanation:

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3 years ago
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