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kenny6666 [7]
2 years ago
14

Sarah cycles 30 miles to her grandmother’s house at a steady speed of 10 mph. If she leaves home at 2:00 pm, what time will she

arrive?
Physics
1 answer:
AfilCa [17]2 years ago
8 0

Answer:

5:00p.m

She is traveling 30 miles and moves 10 miles for each hour therefore 30/10=3

This means she cycled for 3 hours adding this to our time we then have 5p.m

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Answer:

<em>Part A</em><em>:</em>

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<em>Part B</em><em>:</em>

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                      \vartriangle y =\frac{m \lambda L}{d}

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  1. m is the order number.
  2. \lambda is the wavelength of the monochromatic light.
  3. L is the distance between the screen and the two slits.
  4. d is the distance between the slits.
  • Part A:  a) In the above equation for the position of bright fringes we can see that if the wavelength of the light \lambda is decreased the overall effect will be that the fringes are going to be closer. That means that the fringe spacing Δy will decrease.
  • Part B:  b) In the above equation for the position of bright fringes we can see that if the spacing between the slits d is decreased the fringes are going to be wider apart. That means the fringe spacing Δy will increase.
  • Part C:  a) In the above equation we can see that if the distance to the screen L is decreased the fringes are going to be closer. That means the fringe spacing Δy will decrease.
  • Part D: We are told that the central maximum is the fringe C that corresponds with m=0. That means that fringe E corresponds with the order number m=2 if we consider it to be the second maximum at the rigth of the central one. To calculate how much farther from the left slit than from the right slit is a dot located at  the center of the fringe E in the screen we use the condition for constructive interference. That says that the  path length difference Δr between rays coming from the left and right slit must be \vartriangle r=m \lambda

        We simply replace the values in that equation :

                      \vartriangle r= m \lambda =2.\ 460\ nm

                      \vartriangle r= 920\ x\ 10^{-9} m

         The dot in the center of fringe E is 920\ x\ 10^{-9}m farther from the left slit than from the right slit.

     

       

       

     

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