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kenny6666 [7]
3 years ago
14

Sarah cycles 30 miles to her grandmother’s house at a steady speed of 10 mph. If she leaves home at 2:00 pm, what time will she

arrive?
Physics
1 answer:
AfilCa [17]3 years ago
8 0

Answer:

5:00p.m

She is traveling 30 miles and moves 10 miles for each hour therefore 30/10=3

This means she cycled for 3 hours adding this to our time we then have 5p.m

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Which statement about tempture is correct
motikmotik

Answer:

B temperature is an indirect measurement of the heat energy in a substance

Explanation:

The concept of temperature can be easily understood by looking at what happens when two objects are placed in contact with each other. By common experience, we know that the hotter object transfers heat energy to the colder object, until the two objects are in thermal equilibrium (= they have same temperature).

Thinking about the example above, we can say therefore that the temperature is an indirect measurement of the heat energy possessed by an object (or substance).

For a monoatomic gas, for instance, we define its internal energy as

U=\frac{3}{2}nRT

where n is the number of moles, R is the gas constant, and T is the absolute temperature. From the formula, we see that the temperature is related to the internal energy of the gas, so measuring the temperature means indirectly measuring its internal energy.

7 0
3 years ago
34.1 grams / 1.1 mL =
nataly862011 [7]

Answer:

31,000kg/m^3

Explanation:

Hopefully this helps

6 0
3 years ago
Imagine a negative test charge sitting at the coordinate origin (0,0). Two bunches of positive charges are located on the x-axis
Oxana [17]

Answer:

the total force vector, on test charge is points from origin to point C( 1, 1 )

Explanation:

Given the data in the question, as illustrated in the image below;

from the Image, OA = 1, OB = AC = 1

so using Pythagoras theorem

a² = b² + c²

a = √( b² + c² )

so

OC = √( OB² + AC² )

we substitute

OC = √( OA² + AC² )

OC = √( 1² + 1² )

OC = √( 1 + 1 )

OC = √2

Coordinate of C( 1, 1 )

Hence, the total force vector, on test charge is points from origin to point C( 1, 1 )

5 0
3 years ago
A soccer player kicks a ball with a force of 900 newtons. The ball has a mass of 0.5 kilograms. At what rate will the ball accel
Volgvan

Answer:

1800 m/s^{2}

Explanation:

We know this because of Newton's first law, F=ma, which shows us that the force on an object is equal to its mass times the acceleration it recieves. This means that taking our values of 900N and 0.5kg, and plugging them in,

900N=(0.5kg)*(1800m/s^2)

This is honestly a little strange because the force applied and the acceleration seem ridiculous, and a little strange for an answer. Either the values are not meant to be nearly close to reality, or you made a typo.

6 0
3 years ago
A helicopter carrying Dr. Evil takes off with a constant upward acceleration of 5.0 m/s2. Secret agent Austin Powers jumps on ju
denpristay [2]

Answer:

a) h=250\ m

b) \Delta h=0.0835\ m

Explanation:

Given:

  • upward acceleration of the helicopter, a=5\ m.s^{-2}
  • time after the takeoff after which the engine is shut off, t_a=10\ s

a)

<u>Maximum height reached by the helicopter:</u>

using the equation of motion,

h=u.t+\frac{1}{2} a.t^2

where:

u = initial velocity of the helicopter = 0 (took-off from ground)

t = time of observation

h=0+0.5\times 5\times 10^2

h=250\ m

b)

  • time after which Austin Powers deploys parachute(time of free fall), t_f=7\ s
  • acceleration after deploying the parachute, a_p=2\ m.s^{-2}

<u>height fallen freely by Austin:</u>

h_f=u.t_f+\frac{1}{2} g.t_f^2

where:

u= initial velocity of fall at the top = 0 (begins from the max height where the system is momentarily at rest)

t_f= time of free fall

h_f=0+0.5\times 9.8\times 7^2

h_f=240.1\ m

<u>Velocity just before opening the parachute:</u>

v_f=u+g.t_f

v_f=0+9.8\times 7

v_f=68.6\ m.s^{-1}

<u>Time taken by the helicopter to fall:</u>

h=u.t_h+\frac{1}{2} g.t_h^2

where:

u= initial velocity of the helicopter just before it begins falling freely = 0

t_h= time taken by the helicopter to fall on ground

h= height from where it falls = 250 m

now,

250=0+0.5\times 9.8\times t_h^2

t_h=7.1429\ s

From the above time 7 seconds are taken for free fall and the remaining time to fall with parachute.

<u>remaining time,</u>

t'=t_h-t_f

t'=7.1428-7

t'=0.1428\ s

<u>Now the height fallen in the remaining time using parachute:</u>

h'=v_f.t'+\frac{1}{2} a_p.t'^2

h'=68.6\times 0.1428+0.5\times 2\times 0.1428^2

h'=9.8165\ m

<u>Now the height of Austin above the ground when the helicopter crashed on the ground:</u>

\Delta h=h-(h_f+h')

\Delta h=250-(240.1+9.8165)

\Delta h=0.0835\ m

5 0
3 years ago
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