The total charge on the interior of the conductor is zero.
The total charge on the exterior of the conductor is 8q.
<h3>
Total charge on the interior</h3>
Due to large number of electrons available for conduction in a conductor, most of the electrons moves to surface leaving zero net charge inside the conductor.
Thus, the total charge on the interior of the conductor is zero.
<h3>T
otal charge on the exterior</h3>
The total charge on the exterior of the conductor is calculated as follows;
Q = q + 7q = 8q
Thus, the total charge on the exterior of the conductor is 8q.
Learn more about net charge on interior and exterior of conductors here: brainly.com/question/14653264
Displacement from the center line for minimum intensity is 1.35 mm , width of the slit is 0.75 so Wavelength of the light is 506.25.
<h3>How to find Wavelength of the light?</h3>
When a wave is bent by an obstruction whose dimensions are similar to the wavelength, diffraction is observed. We can disregard the effects of extremes because the Fraunhofer diffraction is the most straightforward scenario and the obstacle is a long, narrow slit.
This is a straightforward situation in which we can apply the
Fraunhofer single slit diffraction equation:
y = mλD/a
Where:
y = Displacement from the center line for minimum intensity = 1.35 mm
λ = wavelength of the light.
D = distance
a = width of the slit = 0.75
m = order number = 1
Solving for λ
λ = y + a/ mD
Changing the information that the issue has provided:
λ = 1.35 * 10^-3 + 0.75 * 10^-3 / 1*2
=5.0625 *10^-7 = 506.25
so
Wavelength of the light 506.25.
To learn more about Wavelength of the light refer to:
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Hi
The answer to this question is B. Reaction
Answer:
e)
Explanation:
In an RC series circuit, at any time, the sum of the voltages through the resistor and the capacitor must be constant and equal to the voltage of the DC voltage source, in order to be compliant with KVL.
At= 0, as the voltage through the capacitor can't change instantaneously, all the voltage appears through the resistor, which means that a current flows, that begins to charge the capacitor, up to a point that the voltage through the capacitor is exactly equal to the DC voltage, so no current flows in the circuit anymore, and the charge in the capacitor reaches to its maximum value.
Answer:
wavelength 
= 437.27 nm
Explanation:
given data
first bright fringe = 2.96 mm
slit separation = 0.325 mm
distance D = 2.20 m
solution
we know that this is double slit experiment
so we apply here Fringe width formula that is
β = 
....................1
is Wavelength of light and D is Distance between screen and slit and d is slit width
so put here value and we get
= 
= 437.27 × 
m
wavelength = 437.27 nm
