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jok3333 [9.3K]
3 years ago
11

Ellie’s bird feeder is shaped like a cone with a height of 25 in. and a radius of 3 in. Packages of bird seed are cylindrical an

d come in different sizes.
What is the height of the package that has a radius of 5 in. and contains exactly enough bird seed to fill the feeder? Use 3.14 to approximate pi.



___ in.
Mathematics
1 answer:
Olegator [25]3 years ago
6 0
3 in is the answer how old are you this is easy
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You need to buy a 12 foot length of 25 foot wide carpet that costs 2.60 dollars per square feet how much will this cost
FromTheMoon [43]
The sqft for an area that is 12 by 25 is 300.
2.60 x 300 = 780
It would cost $780.00.
Hope it helps!
4 0
3 years ago
Hi again, I need some help in math this time
alexgriva [62]
The answer to this is y=13
7 0
3 years ago
Read 2 more answers
Help answer the last two and if u wanna check to see if the first one is correct
anzhelika [568]

Answer:

Step-by-step explanation:

7 0
3 years ago
Find a decomposition of a=⟨−5,−1,1⟩ into a vector c parallel to b=⟨−6,0,6⟩ and a vector d perpendicular to b such that c+d=a.
dezoksy [38]

The projection of vector A <em>parallel</em> to vector B is \langle -3, 0, 3\rangle and the projection of vector A <em>perpendicular</em> to vector B is \langle -2, -1, -2\rangle.

In this question, we need to determine all projections of a vector with respect to another vector. In this case, the projection of vector A <em>parallel</em> to vector B is defined by this formula:

\vec a_{\parallel , \vec b} = \frac{\vec a \,\bullet\,\vec b}{\|\vec b\|^{2}}\cdot \vec b (1)

Where \|\vec b\| is the norm of vector B.

And the projection of vector A <em>perpendicular</em> to vector B is:

\vec a_{\perp, \vec b} = \vec a - \vec a_{\parallel, \vec b} (2)

If we know that a = \langle -5, -1, 1 \rangle and \vec b = \langle -6, 0, 6 \rangle, then the projections are now calculated:

\vec a_{\parallel, \vec b} = \frac{(-5)\cdot (-6)+(-1)\cdot (0)+(1)\cdot (6)}{(-6)^{2}+0^{2}+6^{2}} \cdot \langle -6, 0, 6 \rangle

\vec a_{\parallel, \vec b} = \frac{1}{2}\cdot \langle -6, 0, 6 \rangle

\vec a_{\parallel, \vec b} = \langle -3, 0, 3\rangle

\vec a_{\perp, \vec b} = \langle -5, -1, 1 \rangle - \langle -3, 0, 3 \rangle

\vec a_{\perp, \vec b} = \langle -2, -1, -2\rangle

The projection of vector A <em>parallel</em> to vector B is \langle -3, 0, 3\rangle and the projection of vector A <em>perpendicular</em> to vector B is \langle -2, -1, -2\rangle.

We kindly invite to check this question on projection of vectors: brainly.com/question/24160729

7 0
3 years ago
Please help!! (Question in picture) <br> FOR BRAINLIEST + MORE
Oliga [24]

A. 4y(2y + 5) = 4y(2y) + 4y(5) = 8y² + 20y

B. 7a(3a + 8b) = 7a(3a) + 7a(8b) = 21a² + 56ab

C. 13x³(3y + 2x²) = 13x³(3y) + 13x²(2x²) = 39x³y + 26x⁴ units²

D. 7m²(3m - 5) = 7m²(3m) - 7m²(5) = 21m³ - 35m² units²

Ok done. Thank to me :>

5 0
3 years ago
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