An equation is formed of two equal expressions. The quadratic equation that can be used to find x, the smaller number is x²+x-272.
<h3>What is an equation?</h3>
An equation is formed when two equal expressions are equated together with the help of an equal sign '='.
Let the first number be x.
Now since the two numbers are consecutive numbers the other number will be (x+1). Also, it is mentioned in the problem that the product of the two numbers is 272. Therefore, the equation that can represent the product will be,
Thus, the quadratic equation that can be used to find x, the smaller number is x²+x-272.
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Answer:
Step-by-step explanation:
Answer:
She bought 16
Step-by-step explanation:
0.72*16=11.52
Answer:
4×3=12 total cost for the drinks
12.75 + 12= $24.75 total cost for the pizza and drinks combined
The answer:
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x = (⅔)y ;
y = 3x/2.
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Given:
x + (⅓)y + x - (2/4)<span>y - x = (3/6)y ;
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Take the: x + x - x = 1x + 1x - 1x = 2x - 1x = 1x = x ;
and rewrite:
x + (⅓)y - (2/4)y = (3/6)y ;
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Note that: (2/4)y = (<span>½)y ;
and: (3/6)y = (</span><span>½)y ; so;
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Rewrite as:
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</span>x + (⅓)y - (½)y = (½)y ;
Add "(½)y" to EACH SIDE of the equation;
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x + (⅓)y - (½)y + (½)y = (½)y + (½)y ;
to get: x + (⅓)y = y ;
x = 1y - (⅓)y = (3/3) y - (1/3)y - [ (3-1)/3] y = (⅔)y ;
So: x = (<span>⅔)y ;
In terms of "y" ;
Given: </span>(⅔)y = x ; Multiply each side of the equation by "3" ;
3*[(⅔)y] = 3*x ;
to get: 2y = 3x ;
Now, divide EACH SIDE of the equation by "2" ; to isolate "y" on one side of the equation; and to solve for "y" (in terms of "x"):
2y / 2 = 3x / 2 ;
to get:
y = 3x/2 ;
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