Answer:
percentage change from 1960 to 1970 =( 0.11 ÷0.25 ) × 100
= 44 %
Percentage change from 1970 to 1980 =( 0.83 ÷ 0.36) × 100
= 230.55%
percentage change from 1980 to 1990 = ( 0.16 ÷ 1.19) × 100
= 13.44%
percentage change from 1990 to 2000 = (- 0.09 ÷ 1.35) × 100
= -6.667%
Step-by-step explanation:
Item : 1960 1970 1980 1990 2000
gallon: $0.25 $0.36 $1.19 $1.35 $1.26
change : 0.36 - 0.25 = 0.11
percentage change from 1960 to 1970 =( 0.11 ÷0.25 ) × 100
= 44 %
Percentage change from 1970 to 1980 =( 0.83 ÷ 0.36) × 100
= 230.55%
percentage change from 1980 to 1990 = ( 0.16 ÷ 1.19) × 100
= 13.44%
percentage change from 1990 to 2000 = (- 0.09 ÷ 1.35) × 100
= -6.667%
For this case we have the following equation:
r = 9 sin (θ)
In addition, we have the following change of variables:
y = r * sine (θ)
Rewriting the equation we have:
r = 9 sin (θ)
r = 9 (y / r)
r ^ 2 = 9y
On the other hand:
r ^ 2 = x ^ 2 + y ^ 2
Substituting values:
x ^ 2 + y ^ 2 = 9y
Rewriting:
x ^ 2 + y ^ 2 - 9y = 0
Completing squares:
x ^ 2 + y ^ 2 - 9y + (-9/2) ^ 2 = (-9/2) ^ 2
Rewriting:
x ^ 2 + 1/4 (2y-9) ^ 2 = 81/4
4x ^ 2 + (2y-9) ^ 2 = 81
Answer:
The Cartesian equation is:
4x ^ 2 + (2y-9) ^ 2 = 81
The distance between two positions with longitudes A and B is given by ||A| - |B|| if the two positions are at the same side of the meridian (0 degrees longitude) and |A| + |B| if both positions are at different sides of the meridian.
Given that <span>Moscow is at 37.62 degrees longitude and Brasilia is at -47.87
degrees longitude, thus the two cities are at different sides of the meridian.
Therefore, the distance </span><span>(in degrees) between the longitude lines of Moscow and Brasilia</span> is |37.62| + |-47.87| = 37.62 + 47.87 = 85.49
Answer:
Step-by-step explanation:
You can find your answer in attached document.
Answer:
c
Step-by-step explanation:
0.1=1/10
1/10 is just the fraction form of 0.1
