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marissa [1.9K]
3 years ago
9

Gabriel applies for a home loan and, mark signs the agreement promising to pay off the debt in case gabriel fails to do so. in t

his case mark is:
a. the cosigner be. the obligee

c. the obligor

d. the assignor
Business
1 answer:
Gemiola [76]3 years ago
6 0
The answer is letter a, cosigner. Mark is a cosigner is someone who is in charged of the other person's debt when that person he's in signed with wasn't able to meet the requirements or fail to pay or comply. That is why Mark is considered to be a cosigner of Gabriel if Gabriel fails to comply to pay the loan and Mark is in charged to settle it if Gabriel fails to do so.
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<em>parse tree or parsing tree</em>

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your company has a registered domain name. you decide to sell portions of the domain name and make it available to others. What
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A university officer wants to know the proportion of registered students that spend more than 20 minutes to get to school. He se
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Answer:

1) We need a random sample. For this case we assume that the sample selected was obtained using the simple random sampling method.

2) We need to satisfy the following inequalities:

n\hat p =25*0.52= 13 \geq 10

n(1-\hat p) = 25*(1-0.52) =12 \geq 10

So then we satisfy this condition

3) 10% condition. For this case we assume that the random sample selected n represent less than 10% of the population size N . And for this case we can assume this condition.

So then since all the conditions are satisfied we can conclude that we can apply the normal approximation given by:

p \sim N (\hat p, \sqrt{\frac{\hat p (1-\hat p)}{n}})

So then the answer for this case would be:

a. Yes.

Explanation:

For this case we assume that the question is: If in the experiment described we can use the normal approximation for the proportion of interest.

For this case we have a sample of n =25

And we are interested in the proportion of registered students that spend more than 20 minutes to get to school.

X = 13 represent the number of students in the sample selected that have a time more than 20 min.

And then the estimated proportion of interest would be:

\hat p = \frac{X}{n}= \frac{13}{25}= 0.52

And we want to check if we can use the normal approximation given by:

p \sim N (\hat p, \sqrt{\frac{\hat p (1-\hat p)}{n}})

So in order to do this approximation we need to satisfy some conditions listed below:

1) We need a random sample. For this case we assume that the sample selected was obtained using the simple random sampling method.

2) We need to satisfy the following inequalities:

n\hat p =25*0.52= 13 \geq 10

n(1-\hat p) = 25*(1-0.52) =12 \geq 10

So then we satisfy this condition:

3) 10% condition. For this case we assume that the random sample selected n represent less than 10% of the population size N . And for this case we can assume this condition.

So then since all the conditions are satisfied we can conclude that we can apply the normal approximation given by:

p \sim N (\hat p, \sqrt{\frac{\hat p (1-\hat p)}{n}})

So then the answer for this case would be:

a. Yes.

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Answer:

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All of the answers above.
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