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4 years ago

12

Twice a number plus twice a second number is 310. The difference between the numbers is 55. Find the numbers by writing and solv

ing a system of equations. Explain how you solved the system.

1 answer:

Alexus [3.1K]4 years ago

4 0

Answer:

2x+2y=310

x-y=55

multiply seond equation by 2 and adding to first equation

2x-2y=110

add

2x-2y=110

2x+2y=310 +

4x+0y=420

4x=420

divide 4

x=105

sub

x-y=55

105-y=55

minuse 105

-y=-50

mult -1

y=50

the numbers are 105 and 50

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<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

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Exponents
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<u>Algebra I</u>

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$Solution, solve\:for\:x,\:-2\left|2.2x-3.3\right|=-6.6\quad :\quad x=0\quad \mathrm{or}\quad \:x=3$

$Steps:$

$-2\left|2.2x-3.3\right|=-6.6$

$\mathrm{Divide\:both\:sides\:by\:}-2,\\\frac{-2\left|2.2x-3.3\right|}{-2}=\frac{-6.6}{-2}$

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$|f\left(x\right)|=a\quad \Rightarrow \:f\left(x\right)=-a\quad \mathrm{or}\quad \:f\left(x\right)=a,\\2.2x-3.3=-3.3\quad \quad \mathrm{or}\quad \:\quad \:2.2x-3.3=3.3$

$2.2x-3.3=-3.3,\\\mathrm{Add\:}3.3\mathrm{\:to\:both\:sides},\\2.2x-3.3+3.3=-3.3+3.3,\\\mathrm{Refine},\\2.2x=0,\\\mathrm{Multiply\:both\:sides\:by\:}10,\\.2x\cdot \:10=0\cdot \:10,\\\mathrm{Refine},\\22x=0,\\\mathrm{Divide\:both\:sides\:by\:}22,\\\frac{22x}{22}=\frac{0}{22},\\\mathrm{Simplify},\\x=0$

$2.2x-3.3=3.3,\\\mathrm{Multiply\:both\:sides\:by\:}10,\\2.2x\cdot \:10-3.3\cdot \:10=3.3\cdot \:10,\\\mathrm{Refine},\\22x-33=33,\\\mathrm{Add\:}33\mathrm{\:to\:both\:sides},\\22x-33+33=33+33,\\\mathrm{Simplify},\\22x=66,\\\mathrm{Divide\:both\:sides\:by\:}22,\\\frac{22x}{22}=\frac{66}{22},\\\mathrm{Simplify},\\x=3$

$\mathrm{Combine\:the\:ranges},\\x=0\quad \mathrm{or}\quad \:x=3$

$\mathrm{The\:Correct\:Answer\:is\:x=0\quad \mathrm{or}\quad \:x=3}$

$\mathrm{Hope\:This\:Helps!!!}$

$\mathrm{-Austint1414}$

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