Question

3x^2+7x-24=13x Please help me

Answer 1

Step 1. Move all terms to one side.

$3 x^{2} +7x-24-13x=0$

Step 2. Simplify $3 x^{2} +7x-24-13x=0$ to $3 x^{2} -6x-24$

$3 x^{2} -6x-24=0$

Step 3. Factor out the common term 3

$3( x^{2} -2x-8)=0$

Step 4. Factor $x^{2} - 2^{x} -8$

1. Ask: Which two numbers add up to -2 and multiply to -8?

2.  Answer: -4 and 2

3. Rewrite the expression as $(x-4)(x+2):$

$3(x-4)(x+2)=0$

Step 5. solve for $x$

1. Ask: When will $(x-4)(x+2)$ equal zero?

2. Answer: When $x-4=0$ or $x+2=0$

3. Solve each of the 2 equations above:

$x=4,2$

Done! :) $x=4,2$ is your answer.