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torisob [31]
3 years ago
10

True False The explicit location always tells you where users are located when they type the query.

Computers and Technology
2 answers:
gregori [183]3 years ago
7 0
It's true for only some users
givi [52]3 years ago
7 0
She's right The Answer is True
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2. Write these functions definitions:
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Answer:

Complete the code with the following code segment:

void add2Numbers(){

   int num1, num2;

   cout<<"Enter any two numbers: ";

   cin>>num1>>num2;

   cout<<num1+num2;

}

void sub2Numbers(){

   int num1, num2;

   cout<<"Enter any two numbers: ";

   cin>>num1>>num2;

   cout<<num1-num2;

}

void mul2Numbers(){

   int num1, num2;

   cout<<"Enter any two numbers: ";

   cin>>num1>>num2;

   cout<<num1*num2;

}

void div2Numbers(){

   int num1, num2;

   cout<<"Enter any two numbers: ";

   cin>>num1>>num2;

if(num2==0){

cout<<"Division by 0 is invalid";

}else{

   cout<<(float)num1/num2;}

}

Explanation:

The function added to this solution are:

  • add2Numbers
  • sub2Numbers
  • mul2Numbers
  • div2Numbers

Each of the functions

  • declares two integers num1 and num2
  • prompt user for inputs
  • gets user inputs from the user

For add2Numbers() function:

This line adds the two integer numbers and prints the result

   cout<<num1+num2;

For sub2Numbers() function:

This line subtracts the two integer numbers and prints the result

   cout<<num1-num2;

For mul2Numbers() function:

This line multiplies the two integer numbers and prints the result

   cout<<num1*num2;

For div2Numbers() function:

This if condtion checks if the denominator is 0

if(num2==0){

If yes, the following is printed

cout<<"Division by 0 is invalid";

If otherwise, the division is calculated and the result is printed

   cout<<(float)num1/num2;

<em>See attachment for complete program</em>

Download cpp
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