Answer:
A. delete the message without opening it.
Explanation:
Never open emails you don't know who sent it, it could be a hacker trying to get your personal/financial information.
Answer:
function countWords(sentence) {
return sentence.match(/\S+/g).length;
}
const sentence = 'This sentence has five words ';
console.log(`"${sentence}" has ${countWords(sentence)} words` );
Explanation:
Regular expressions are a powerful way to tackle this. One obvious cornercase is that multiple spaces could occur. The regex doesn't care.
Answer:
import java.util.Scanner;
public class num8 {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
System.out.println("Enter the mass");
double mass = in.nextDouble();
double weight = calWeight(mass);
System.out.println("The weigth is "+weight);
}
static double calWeight(double mass){
double weight = mass*9.80665; // assume a = accelation due to gravity = 9.80665N
if(weight>500){
System.out.println("Too Heavy");
}
else if(weight<100){
System.out.println("Too Light");
}
return weight;
}
}
Explanation:
- Using Java programming language
- The main method is created to request and store a variable, mass in kilogram. The main method call calWeight() and passes the value for mass
- A method calWeight() is created that calculates the weight in newtons (mass * 9.8).
- The method checks if the weight is greater than 500 (prints too heavy) if less than 100(prints to light)
- Returns the weight
If you're coding with C++ then the solution would be:
if (userInput.find("darn") != -1) {
cout << "Censored" << endl;
}
else{
cout << userInput << endl;
}
Keep in mind that this will reject any input with the word "darn" in the sentence. This will not filter the word darn if the capitalization is in different formats like "Darn, dArn, daRn, darN, DARN".
