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Masteriza [31]
3 years ago
7

Suppose that you have a multiplexer (mux) with 5 different inputs at the following bit-rates: (A) 20 Kbps, (B) 8 Kbps, (C) 12 Kb

ps, (D) 8 Kbps, and (E) 4 Kbps. Using a fixed slot size in the frame, how would you organize a single asynchronous TDM link receiving the output of the mux
Computers and Technology
1 answer:
sweet [91]3 years ago
7 0
The answer is number:

C.- Kbps
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Read 3 more answers
Add three methods to the Student class that compare twoStudent objects. One method (__eq__) should test for equality. A second m
shusha [124]

Answer:

class Student(object):

def __init__(self, name, number):

self.name = name

self.scores = []

for count in range(number):

self.scores.append(0)

 

def getName(self):

 

return self.name

 

def setScore(self, i, score):

 

self.scores[i - 1] = score

 

def getScore(self, i):

 

return self.scores[i - 1]

 

def getAverage(self):

 

return sum(self.scores) / len(self._scores)

 

def getHighScore(self):

 

return max(self.scores)

def __eq__(self,student):

return self.name == student.name

 

def __ge__(self,student):

return self.name == student.name or self.name>student.name

 

def __lt__(self,student):

return self.name<student.name

 

def __str__(self):

return "Name: " + self.name + "\nScores: " + \

" ".join(map(str, self.scores))

 

 

def main():

student = Student("Ken", 5)

print(student)

for i in range(1, 6):

student.setScore(i, 100)

print(student)

 

print("\nSecond student")

student2 = Student("Ken", 5)

print(student2)

 

print("\nThird student")

student3 = Student("Amit", 5)

print(student3)

 

print("\nChecking equal student1 and student 2")

print(student.__eq__(student2))

 

print("\nChecking equal student1 and student 3")

print(student.__eq__(student3))

 

print("\nChecking greater than equal student1 and student 3")

print(student.__ge__(student3))

 

print("\nChecking less than student1 and student 3")

print(student.__lt__(student3))

if __name__ == "__main__":

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3 years ago
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