The equation of the line that is parallel and passes through the point (2,3) is; x +2y =8.
<h3>What is the equation of the line that passes through (2,3)?</h3>
If follows from the task content that the slope of the first line is; (-4-0)/(4-(-4)) = -1/2.
Hence, since the lines are parallel, they have the same slope and the equation of the second line is;
-1/2 = (y-3)/(x-2)
-x+2 = 2y -6
x +2y =8.
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Answer:
The Answer is: y = -2/3x + 10/3
Step-by-step explanation:
Given points (-1, 4) and (8, -2) first find the slope:
m = (y - y1)/(x - x1)
m = (4 - (-2)) / (-1 - 8)
m = 4 + 2 / -9
m = -6/9 = -2/3
Use the point slope form and point (8, -2) and slove for y:
y - y1 = m(x - x1)
y - (-2) = -2/3(x - 8)
y + 2 = -2/3x + 16/3
y = -2/3x + 16/3 - 2
y = -2/3x + 16/3 - 6/3
y = -2/3x + 10/3
Proof using the point (-1, 4):
f(-1) = -2/3(-1) + 10/3
= 2/3 + 10/3
= 12/3 = 4, giving point (-1, 4)
Hope this helps! Have an Awesome Day!! :-)
Answer:
-32-p
Step-by-step explanation:
you combine the like terms which would be -21 and -11. that gives you -32 and -p is just by its self since there are no terms to combine it with
