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3 years ago

Plssssss help me with this math pls

Mathematics

1 answer:

sdas [7]3 years ago

4 0

Answer:

The correct answer is A) 4/663.

Step-by-step explanation:

First you find the probability of drawing a queen when drawing a single card from a deck of 52 cards. Since there are 4 queens(the queen of diamond, the queen of hearts, the queen of spades, and the queen of clubs) in a deck of 52 cards, the probability of drawing a queen when drawing a single card from a deck of 52 cards is 4/52.

Next you find the probability of drawing a king when drawing a single card from a deck of 51 cards(since you did not replace the first card you drew). Since there are 4 kings(the king of diamond, the king of hearts, the king of spades, and the king of clubs) in a deck of cards, the probability of drawing a king when drawing a single card from a deck of 51 cards is 4/51.

Then you multiply the two probabilities to determine the probability of drawing a queen then a king. So,

4/52 x 4/51 =

4 x 4/52 x 51 =

16/2652

Finally, simplify the fraction. The greatest number that can go into both the numerator and denominator is 4. So divide both the numerator and denominator by 4. When you do this, you get the following:

16 divided by 4 = 4 as the numerator and

2652 divided by 4 = 663 as denominator.

So, the final answer is 4/663.

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Which of the following equations represents a line with a negative slope and a negative y-intercept?

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3 years ago

Which best describe a vector

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Answer:

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6 0

3 years ago

Assume that a sample is used to estimate a population proportion μ . Find the margin of error M.E. that corresponds to a sample

hichkok12 [17]

Answer:

$MoE = 1.645\cdot \frac{13.1}{\sqrt{772} } \\\\MoE = 1.645\cdot 0.47147\\\\MoE = 0.776\\\\$

Step-by-step explanation:

Since the sample size is quite large, we can use the z-distribution.

The margin of error is given by

$MoE = z_{\alpha/2}(\frac{s}{\sqrt{n} } )$

Where n is the sample size, s is the sample standard deviation and $z_{\alpha/2}$ is the z-score corresponding to a 90% confidence level.

The z-score corresponding to a 90% confidence level is

Significance level = α = 1 - 0.90= 0.10/2 = 0.05

From the z-table at α = 0.05

z-score = 1.645

$MoE = 1.645\cdot \frac{13.1}{\sqrt{772} } \\\\MoE = 1.645\cdot 0.47147\\\\MoE = 0.776\\\\$

Therefore, the margin of error is 0.776.

3 0

3 years ago

Translate the Variable Expression 3n -7 into Verbal Expression

sp2606 [1]

Step-by-step explanation:

$3n-7\\\\\text{The difference between three times the number n and seven.}$

8 0

3 years ago

Please help if you can pic attatched

MA_775_DIABLO [31]

Answer:

Step-by-step explanation:

$CI=\left[\begin{array}{ccc}1&6&0\\0&1&2\\1&-1&3\end{array}\right] \left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right]$

Subtract row 3 from row 1:

$\left[\begin{array}{ccc}1&6&0\\0&1&2\\0&7&-3\end{array}\right] \left[\begin{array}{ccc}1&0&0\\0&1&0\\1&0&-1\end{array}\right]$

Subtract row 3 from 7 times row 2:

$\left[\begin{array}{ccc}1&6&0\\0&1&2\\0&0&17\end{array}\right] \left[\begin{array}{ccc}1&0&0\\0&1&0\\-1&7&1\end{array}\right]$

Divide row 3 by 17:

$\left[\begin{array}{ccc}1&6&0\\0&1&2\\0&0&1\end{array}\right] \left[\begin{array}{ccc}1&0&0\\0&1&0\\\frac{-1}{17} &\frac{7}{17} &\frac{1}{17} \end{array}\right]$

Subtract 2 of row 3 from row 2:

$\left[\begin{array}{ccc}1&6&0\\0&1&0\\0&0&1\end{array}\right] \left[\begin{array}{ccc}1&0&0\\\frac{2}{17} &\frac{3}{17} &\frac{-2}{17} \\\frac{-1}{17} &\frac{7}{17} &\frac{1}{17} \end{array}\right]$

Subtract 6 of row 2 from row 1:

$\left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right] \left[\begin{array}{ccc}\frac{5}{17}&\frac{-18}{17}&\frac{12}{17}\\\frac{2}{17} &\frac{3}{17} &\frac{-2}{17} \\\frac{-1}{17} &\frac{7}{17} &\frac{1}{17} \end{array}\right]$

$C^{-1}=\frac{1}{17} \left[\begin{array}{ccc}5&-18&12\\2&3&-2\\-1&7&1\end{array}\right]$

$C^{-1}b=\frac{1}{17} \left[\begin{array}{ccc}5&-18&12\\2&3&-2\\-1&7&1\end{array}\right]\left[\begin{array}{c}10&1&3\end{array}\right]=\left[\begin{array}{c}4&1&0\end{array}\right]$

3 0

3 years ago