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MrRissso [65]
2 years ago
7

Do-nothing #1 can count 5 more ceiling dots

Mathematics
1 answer:
klasskru [66]2 years ago
5 0

Answer:

2

Step-by-step explanation:

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In polar coordinates, the axis determined by theta=0 is called ?
melisa1 [442]

In polar coordinates, the axis determined by theta=0 is called the positive x-axis or horizontal axis.

To add, in mathematics, the polar coordinate<span> system is a two-dimensional </span>coordinate<span> <span>system in which each point on a plane is determined by a distance from a reference point and an angle from a reference direction.</span></span>

4 0
3 years ago
Read 2 more answers
Pls show full working out
sweet-ann [11.9K]

Answer:

  • Question 1a. i) x=1.8m

  • Question 1a. ii)   Volume=27.6m^3

  • Question 1b) Volume=65.9m^3

Explanation:

<u><em>Question 1 a. i) Find the value of x.</em></u>

         tan(\theta )=\dfrac{opposite\text{ }leg}{adjacent\text{ }leg}

For the smalll triangle you can write:

        tan(\theta )=\dfrac{x}{1m}

For tthe big triangle:

      tan(\theta )=\dfrac{x+2.7m}{2.5m}

Substitute:

        \dfrac{x}{1m}=\dfrac{x+2.7m}{2.5m}

Solve for x:

        2.5x=x+2.7m\\\\2.5x-x=2.7m\\\\1.5x=2.7m\\\\x=2.7m/1.5\\\\x=1.8m

<u><em>Question 1a ii) Find the volume of the frustrum</em></u>

  • Find the volume of a cone with height = 2.7m + 1.8m = 4.5m, and radius = 2.5m

Formula:

         Volume=(1/3)\pi \times radius^2\times height

Substitute:

         Volume=(1/3)\pi \times (2.5m)^2\times 4.5m=9.375\pi m^3

  • Find the volume of a cone with heigth = 1.8m and radius = 1m

        Volume=(1/3)\pi \times (1m)^2\times 1.8m=0.6\pi m^3

  • Subtract the volume of the small cone from the volume of the big cone

        Volume\text{ }of\text{ }frustrum=9.375\pi m^3-0.6\pi m^3=8.775\pi m^3\approx 27.6m^3

<u><em>Question 1b. Calculate the volume of the bin</em></u>

<u>i) Upper frustrum</u>

This is the same frustrum from the equation of above, thus ist volume is 27.6m³.

<u>ii) Lower frustrum</u>

            \dfrac{x}{2.0m}=\dfrac{x+2.4m}{2.5m}

           2.5x=2(x+2.4m)\\\\2.5x=2x+4.8m\\\\0.5x=4.8m\\\\x=9.6m

        Volume=(1/3)\pi \times (2.5m)^2\times (9.6m+2.4m)-(2.0m)^2\times (9.6m)

       Volume=38.3m^3

<u>iii) Add the volume of the two frustrums</u>

  • Volume=27.6m^3+38.3m^3=65.9m^3

6 0
3 years ago
What is 6 divided by 3999 divided by 10021
Dvinal [7]

Answer:

0.00000014972309

Step-by-step explanation:

6/3999=0.00150037509

0.00150037509/10021=  0.00000014972309

hope this helps

4 0
3 years ago
Please helppppppp!!!!!!!!!!!!!!!!!!!!!!!!!!!
Olin [163]

So here, ABCD is being inscribed in a circle, so ABCD is a cyclic quadrilateral (as inscribed in a circle) also, there exists a property of cyclic quadrilateral, i.e, the sum of opposite angles of a cyclic quadrilateral is 180°, so we can just write the following equation using this :

{:\implies \quad \sf y^{\circ}+83^{\circ}=180^{\circ}}

{:\implies \quad \sf y^{\circ}=180^{\circ}-83^{\circ}}

{:\implies \quad \sf y^{\circ}=97^{\circ}}

{:\implies \quad \boxed{\bf{y=97}}}

6 0
2 years ago
Two ropes, AD and BD, are tied to a peg on the ground at point D. The other ends of the ropes are tied to points A and B on a fl
Lisa [10]

Answer: 5(√3-1) unit.

Step-by-step explanation:

Since, By the below diagram,

For triangle BDC,

We can write,

tan 30^{\circ}=\frac{BC}{DC}

⇒ \frac{1}{\sqrt{3}}=\frac{BC}{5\sqrt{3}}}

⇒  \sqrt{3}=\frac{5\sqrt{3}}{BC}

⇒ BC=\frac{5\sqrt{3} }{\sqrt{3} }

⇒ BC=5\text{ unit}

Now, In triangle ADC,

tan45^{\circ}=\frac{AC}{DC}

⇒ 1=\frac{AB+BC}{DC}

⇒ 1=\frac{DC}{AB+BC}

⇒ 1=\frac{5\sqrt{3}}{AB+5}

⇒ AB+5=5\sqrt{3}

⇒ AB=5\sqrt{3}-5=5(\sqrt{3}-1)\text{ unit}

8 0
3 years ago
Read 2 more answers
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