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Sav [38]
3 years ago
8

If the leading coefficient of a quadratic function is negative then the graph of the function extends from?

Mathematics
2 answers:
12345 [234]3 years ago
7 0
I'm not sure what you mean by "extends from", but a negative leading coefficient of a quadratic causes it to become concave, as in extending downwards. For y = -x^2, the function's maximum is 0.
coldgirl [10]3 years ago
5 0
I wouldn't use the phrase "extends from."  If the leading coeff. is neg, then the graph opens downward.  Without more info we do not know the max of this fn.  If we did know it, we could state that the graph max is (value) and that the graph "extends downward from this value."

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lara [203]

Hello from MrBillDoesMath!

Answer:

Top line: y = (2/3)x + 2

Bottom line:  y = (2/3)x  -1

Discussion:

The graph provided is hard to read but I did the best I could.

The top line appears to pass through the points (0,2) and (-3,0)

For this line

m =  change y /change x = (0-2)/(-3-0) = -2/-3 = +2/3. So

y = mx + b => y = (2/3) x+ b.  As the line passes through (0,2) set x = 0, y= 2 in y = (2/3)x + b =>  

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The bottom line appears to pass through the points (0,-1) and (3,1)

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m =  change y /change x = (1-(-1)) /(3-0) = +2/-3. So

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Therefore    y = (2/3)x + -1

Thank you,

MrB

5 0
3 years ago
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