All categories

3 years ago

Write an algebraic expression to find the AREA of a rectangle with a length of 4x-5 and a width of 7.

Mathematics

1 answer:

blagie [28]3 years ago

8 0

Answer:

28x-35

Step-by-step explanation:

4x*7=28x

5*7=35

You might be interested in

Please answer correctly. Thanks! Will mark brainliest

PSYCHO15rus [73]

Answer:

$x=2\\y=22\\or\\(2,22)$

Step-by-step explanation:

$x+y=24\\y=11x$

Subtitute y in the first equation.

$x+y=24\\x+11x=24\\12x=24\\x=\frac{24}{12}\\ x=2$

Now replace x in either equation to find y.

$y=11x\\y=11(2)\\y=22$

5 0

3 years ago

Read 2 more answers

For f(x) = 4x+ 1 and g(x) = x2 - 5, find (f+ g)(x).

horrorfan [7]

Answer:

x^2+4x-4

Step-by-step explanation:

4x+1+x^2-5

x^2+4x-4

6 0

3 years ago

Read 2 more answers

AD = 6x - 4 and AC = 4x - 3

salantis [7]

Answer:

CD= 2x-1

Step-by-step explanation:

AD = 6x-4

AC = 4x - 3

CD= AD- AC

CD= 6x-4 - (4x - 3)

CD= 6x - 4 - 4x +3

CD= 2x -1

Therefore, the value of CD= 2x-1

3 0

2 years ago

Judy worked 8 hours and Ben worked 10 hours. Their combined pay was $80. When Judy worked 9 hours and Ben worked 5 hours, their

pav-90 [236]

Answer:

Judy = $5/hr

Ben = $4/hr

Step-by-step explanation:

Judy's hours at work - x

Ben's hours at work - y

8x + 10y = 80

9x + 5y = 65

Given these two equations above, we get:

10y = 80 - 8x, which means y = 8 - 0.8x.

Substitute y in the second equation with 8 - 0.8x, so we have:

9x + 5 (8 - 0.8x) = 65

9x + 40 - 4x = 65

5x = 25

x = 5

Come back to the first equation, substitute x:

8*5 + 10y = 80

10y = 80 - 40

y = 4

3 0

3 years ago

) Set up a double integral for calculating the flux of F=3xi+yj+zk through the part of the surface z=−5x−2y+2 above the triangle

Fynjy0 [20]

The surface (call it $S$ ) is a triangle with vertices at the points

$x=0,y=0\implies z=2\implies(0,0,2)$

$x=0,y=2\implies z=-2\implies(0,2,-2)$

$x=2,y=0\implies z=-8\implies(2,0,-8)$

Parameterize $S$ by

$\vec s(u,v)=(1-v)(2,0,-8)+v\bigg((1-u)(0,2,-2)+u(0,0,2)\bigg)=(2-2v,2v-2uv,-8+6v+4uv)$

with $0\le u\le1$ and $0\le v\le1$ . Take the normal vector to $S$ to be

$\vec s_v\times\vec s_u=(20v,8v,4v)$

Then the flux of $\vec F$ across $S$ is

$\displaystyle\iint_S\vec F(x,y,z)\cdot\mathrm d\vec S=\int_0^1\int_0^1\vec F(x(u,v),y(u,v),z(u,v))\cdot(\vec s_v\times\vec s_u)\,\mathrm du\,\mathrm dv$

$=\displaystyle\int_0^1\int_0^1(6-6v,2v-2uv,-8+6v+4uv)\cdot(20v,8v,4v)\,\mathrm du\,\mathrm dv$

$=\displaystyle8\int_0^1\int_0^1(11v-10v^2)\,\mathrm du\,\mathrm dv=\boxed{\frac{52}3}$

8 0

4 years ago