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Goryan [66]
3 years ago
6

I need to know how to solve -4-(2+4(-6)-4-(2^2-5*2))

Mathematics
1 answer:
sweet-ann [11.9K]3 years ago
4 0

Answer:

16

Step-by-step explanation:

This problem requires PEMDAS

Parentheses ( )

Exponents ^

Multiplication

Division

Add

Subtract

Start by solving anything in parentheses. There's an exponent within the parentheses, so we change that 2^2 into 4 and also make sure to multiply 5 x 2 before subtracting.

-4 - (2 + -24 - 4 - (4-10))

-4 - (2 + -24 - 4 - (-6))

Again, solve parentheses first.

-4 - (-22 - 4 - (-6))

-4 - (-26 + 6)

-4 - (-20)

-4 + 20

Answer is 16

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Homework
Zolol [24]

<u><em>Note:</em></u><em> As you have missed to mention the first four terms of the Arithmetic sequence. So, I am randomly assuming that first four terms of the arithmetic sequence be 1, 3, 5, 7... This would anyhow make you understand the concept. So, I am solving your query based on assuming the first four terms of an Arithmetic sequence as 1, 3, 5, 7...</em>

Part A)

<em><u>What is the next term of this sequence?</u></em>

Answer:

{\displaystyle \ a_{5}=9 is the next term i.e. 5th term of the arithmetic sequence <em>1, 3, 5, 7...</em>

Step-by-step explanation:

Considering the Arithmetic sequence with fist four terms

<em> 1, 3, 5, 7...</em>

As we know that a sequence is termed as arithmetic sequence of numbers if the difference of any two consecutive terms of the sequence remains constant.

For instance, <em> 1, 3, 5, 7... </em>will be an arithmetic sequence having the common difference 2. Common difference is denoted by 'd'.

So,

Given the sequence

<em>1, 3, 5, 7...</em>

d=3-1=2,d=5-3=2

As a_{1} = 1 and d = 2

The next term i.e. 5th term can be found by using the nth term of the sequence.

So, consider the nth term of the sequence {\displaystyle a_{n}

{\displaystyle \ a_{n}=a_{1}+(n-1)d}

Putting n=5 in, a_{1} = 1 and d = 2  in {\displaystyle \ a_{n}=a_{1}+(n-1)d} to find the 5th term.

{\displaystyle \ a_{n}=a_{1}+(n-1)d}

{\displaystyle \ a_{5}=1+(5-1)2}

{\displaystyle \ a_{5}=1+(4)2}

{\displaystyle \ a_{5}=9

So, {\displaystyle \ a_{5}=9 is the next term i.e. 5th term of the arithmetic sequence <em>1, 3, 5, 7...</em>

Part B)

<u><em>Writing down an expression,  in terms of n for the nth term of the sequence</em></u>

consider the nth term of the sequence {\displaystyle a_{n}

{\displaystyle \ a_{n}=a_{1}+(n-1)d}

Here, a_{1} is the first term, d is the common difference.

For example,

Given the sequence

<em>1, 3, 5, 7...</em>

d=3-1=2,d=5-3=2

As a_{1} = 1 and d = 2

The next term i.e. 5th term can be found by using the nth term of the sequence.

So, consider the nth term of the sequence {\displaystyle a_{n}

{\displaystyle \ a_{n}=a_{1}+(n-1)d}

Putting n=5 in, a_{1} = 1 and d = 2  in {\displaystyle \ a_{n}=a_{1}+(n-1)d} to find the 5th term.

{\displaystyle \ a_{n}=a_{1}+(n-1)d}

{\displaystyle \ a_{5}=1+(5-1)2}

{\displaystyle \ a_{5}=1+(4)2}

{\displaystyle \ a_{5}=9

Keywords: arithmetic sequence, nth term, common difference

Learn more abut arithmetic sequence, nth term and common difference from brainly.com/question/12227567

#learnwithBrainly

7 0
3 years ago
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