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3 years ago

13

A small class has 9 students, 4 of whom are girls and 5 of whom are boys. The teacher is going to choose two of the students at

random. What is the probability that the first student chosen will be a boy and the second will be a girl?

1 answer:

Mazyrski [523]3 years ago

5 0

20/72 = 10/36 = 5/18

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How mony boxes does Sharice need?<br>sharice needs ? boxes

Ne4ueva [31]

she will need 18 boxes total :)

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2 years ago

Read 2 more answers

Marcus is rewriting a polynomial by combining like terms. Which terms does he still need to combine to finish rewriting the poly

Sunny_sXe [5.5K]

Answer:-3mn^3 and -5mn^3

Step-by-step explanation:

4 0

3 years ago

Several students from boxerville middle stood in a circle, evenly spaced, to play a game. If the 6th student was directly across

myrzilka [38]

Answer:

There were 14 students in the circle

Step-by-step explanation:

* Lets explain how to solve the problem

- The students stood in a circle

∴ The line joining each two opposite students is the diameter

of the circle

- The 6th student was directly across from the 13th student

∴ The 6th student is opposite to the 13th student

- Lets count how many students between 6th student and

13th student

∵ 7th , 8th , 9th , 10th , 11th , 12th students between the 6th

student and 13th student

∴ There are 6 students between them

- Lets count how many students between 13th student and

6th student

∵ 14th , 1st , 2nd , 3rd , 4th , 5th students between the 13th

student and 6th student

∴ There are 6 students between them

∵ There are 6 students between 6th and 13th

∵ There are 6 students between 13th and 6th

∵ There are 2 students in 6th and 13th

∴ The number of the students = 6 + 6 + 2 = 14

∴ There were 14 students in the circle

8 0

4 years ago

Pls answer i’ll give brainliest

oee [108]

Answer:

PQR and JK

Step-by-step explanation:

ΔGHJ ≈ ΔPQR by the Transitive Property of Congruence. GH ≈ JK since corresponding parts of congruent figures are congruent.

Pls mark as brainliest. I would really appreciate it if you did.

4 0

3 years ago

In triangle abc, m of acb = 90, cd is perpendicular to ab , m of acd is 60. and bd is 5 cm. find ad

weeeeeb [17]

Let us draw a picture to make the things more clear.

Attached is the image.

We have been given that

$\angle acd = 60 ^{\circ}$

Therefore, we have

$\angle dcb =90- 60= 30 ^{\circ}$

Now, in triangle bcd, we have

$\tan30 = \frac{5}{cd}\\
\\
\frac{1}{\sqrt 3}=\frac{5}{cd}\\
\\
cd=5\sqrt 3$

Now, in triangle acb, we have

$tan 60 = \frac{ad}{5\sqrt3} \\
\\
\sqrt 3= \frac{ad}{5\sqrt3}\\
\\
ad= 5\sqrt3 \times \sqrt 3\\
\\
ad= 5\times 3\\
\\
ad=15$

Thus, ad is 15 cm.

4 0

3 years ago