we are given
Firstly, we will find domain of c(x) , d(x) and then (cd)(x)
and then we can find common domain
Domain of c(x):
we know that domain is all possible values of x for which domain is defined
we know that any function is undefined when denominator =0
x-2=0
x=2
so, domain of c(x) is all values of x except at x=2
Domain of d(x):
we know that domain is all possible values of x for which domain is defined
we know that any function is undefined when denominator =0
we don't have denominator here
so, domain of d(x) is all real values of x
Domain of (cd)(x):
we know that domain is all possible values of x for which domain is defined
we know that any function is undefined when denominator =0
x-2=0
x=2
so, domain of c(x) is all values of x except at x=2
so, common domain is all real values of x except at x=2
so, option-B........Answer
Camila puso 30 botellas de cada sabor en la estantería.
Dado que Camila ubicó 90 botellas en una estantería de un supermercado, y los jugos sin azúcar tienen tres sabores diferentes y Camila puso la misma cantidad de cada sabor en la estantería, para determinar la cantidad de botellas de jugo sin azúcar de cada sabor que puso Camila en la estantería se debe realizar el siguiente cálculo:
Por lo tanto, Camila puso 30 botellas de cada sabor en la estantería.
Aprende más en brainly.com/question/16991787
Let
x---------> the number
we know that
[9+2x]*4=4x+12
36+8x=4x+12
8x-4x=12-36
4x=-24
x=-24/4
x=-6
the answer is
-6
If I'm not wrong, then the answer will be:-
Given
• centers A, B, C
• three congruent sides
• have no common points
So, the result is:-
| PQ | + | RS | + | TU | = | QR | + | ST | + | UP |
<h3>
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>Proved </em></h3>
I hope this answer is correct and helps you.
✍️ <em>By </em><em>Benjemin</em> ☺️
Answer:
Step-by-step explanation:
ΔPQS, ΔRQP and ΔRPS are similar (AA). Therefore the sides are in proportion:
We have:
Substitute:
<em>cross multiply</em>
Use the Pythagorean theorem:
Substitute: