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3 years ago

What is the quotient? URGENT!!

Mathematics

1 answer:

jeyben [28]3 years ago

5 0

Answer:

The answer is A.

Step-by-step explanation:

You have to multiply by converting the second fraction into upside down :

$\frac{4x + 1}{6x} \div \frac{x}{3x - 1}$

$= \frac{4x + 1}{6x} \times \frac{3x - 1}{x}$

$= \frac{(4x + 1)(3x - 1)}{x(6x)}$

$= \frac{12 {x}^{2} - 4x + 3x - 1}{6 {x}^{2} }$

$= \frac{12 {x}^{2} - x - 1 }{6 {x}^{2} }$

You might be interested in

Graph the function f(x) = 3x-5

nexus9112 [7]

Have a nice day :)

f(0)=3*0-5=-5
3x-5=0
3x=5
x=5/3

=====================================================

5 0

3 years ago

If runners in a long distance race were to run straight from the starting line to the finish line they would run 13 kilometers.

tia_tia [17]

5^2 +x^2 = 13^2

25 + x^2 = 169

x^2 = 144

x = sqrt(144) = 12

they run west for 12 KM

12+5 = 17 total km

7 0

3 years ago

PLEASEE GUYSSS I REALLY NEED HELP ON THISS FASTT!!!

Lostsunrise [7]

Answer:

13. alternate interior

14. linear pair/ none of the above

15. vertical angles

16. corresponding angles

Step-by-step explanation:

4 0

3 years ago

A rocket is launched straight up from the ground with an initial velocity of 192 feet per second. The equation for the height of

Ivenika [448]

The equation for the height of the rocket at time t given

$h= -16t^2+192t$

We have to find the time t, when the rocket reaches 560 feet.

That means we have to find t when h = 560 ft. we will place 560 in the place of h to find t now.

$h= -16t^2+192t$

$560 = -16t^2+192t$

In the right side, we can check -16 is the common factor. So we will take out -16 from the rigbht side.

$560 = -16(t^2 - 12t)$

To get rid of -16 from the right side and move it to left side, we will divide both sides by -16.

$560/-16 = -16(t^2-12t)/-16$

$-35 = t^2 -12t$

Now we will move -35 to the righ side by adding 35 to both sides.

$-35+35 = t^2-12t+35$

$0 = t^2 -12t+35$

$t^2-12t+35 = 0$

We will factorize thee left side to find the values of t now. We need to find a pair of factors of 35 that by adding them we will get -12.

The pair of factors of 35 are -5 and -7 and by adding -5-7 we will get -12.

$t^2-12t+35 =0$

$(t-5)(t-7) =0$

So by using zero product property we will get

$t-5 =0$

$t-5+5 = 0+5$

$t=5$

Also $t-7 =0$

$t-7+7 = 0+7$

$t=7$

So we have got the rocket reaches at 560ft when t = 5 seconds and also when t = 7 seconds.

Now part b.

When the rocket completes its trajectory and hits the ground then the height or h = 0. So we will place h = 0 there in the equation.

$h= -16t^2+192t$

$0= -16t^2 + 192 t$

$0 = -16(t^2-12t)$

$-16(t^2-12t) = 0$

We will move -16 to the other side by dividing it to both sides.

$-16(t^2-12t)/-16 = 0/-16$

$t^2-12t = 0$

We will take out the common factor t from the left side. By taking out t we will get,

$t(t-12) = 0$

We will use zero product property now. By using that we will get,

$t = 0$

ans also $t-12 = 0$

$t-12+12 = 0+12$

$t = 12$

When the rocket completes its trajectory and hits the ground the time t can not be 0. When t =0, the rocket starts the trajectory.

So when the rocket completes its trajectory and hits the ground ,

then t = 12seconds.

So we have got the required answers.

6 0

3 years ago

A teacher wants to buy 9 boxes of granola bars for a school trip. Each box usually costs $7, but many grocery stores are having

Novay_Z [31]

Answer:

well I think the question's not complete but if that's the question then 9 boxes would cost about $63 dollars. since some stores have a sale, you should add the word 'about' or 'around' with the answer. hope it was helpful ))

5 0

3 years ago