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Sever21 [200]
3 years ago
7

Decide if the following scenario involves a permutation or combination. Then find the number of possibilities. The student body

of 165 students wants to elect 3 representatives
Mathematics
1 answer:
Troyanec [42]3 years ago
6 0

Answer:

735,130.

Step-by-step explanation:

The order of election of the 3 representatives does not matter so it is a combination.

The number of possible combinations

= 165! / 162! 3!

=  (165 * 164 * 163) / (3*2*1)

= 735,130.

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Step-by-step explanation:

6 0
2 years ago
What is the probability that a phone number generated using the digits 1, 2, 2, 4, 5, 5, 6, and 2 is the number 654-5222
pochemuha

Answer:

336 ways

Step-by-step explanation:

The digits are 1, 2, 2, 4, 5, 5, 6, and 2 that is total eight digits.

The number 654-5222 contains 7 digits.

So, we have find The number of permutations for choosing 7 digits from 8 digits given above.

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7 0
3 years ago
The proportion of left handed people in the population is about 0.10. Suppose a random sample of 300 people is observed. (a) Wha
pantera1 [17]

Answer: (\hat{p})\sim N(0.10,\ 0.017)

Step-by-step explanation:

Sampling distribution of the sample proportion (\hat{p}) :

(\hat{p})\sim N(p,\ \sqrt{\dfrac{p(1-p)}{n}})

The sampling distribution of the sample proportion (\hat{p}) has mean = \mu_{\hat{p}}=p and standard deviation = \sigma_{\hat{p}}=\sqrt{\dfrac{p(1-p)}{n}}.

Given : The proportion of left handed people in the population is about 0.10.

i.e. p=0.10

sample size : n= 300

Then , the sampling distribution of the sample proportion(\hat{p}) will be :-

(\hat{p})\sim N(0.10,\ \sqrt{\dfrac{0.10(1-0.10)}{300}})

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(\hat{p})\sim N(0.10,\ 0.017)  (approx)

Hence, the sampling distribution of the sample proportion(\hat{p}) is (\hat{p})\sim N(0.10,\ 0.017)

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3 years ago
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9. Modeling Real Life A machine that
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Answer:

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Step-by-step explanation:

so your answer is this hope this helps good luck if it does not i am sorry

7 0
2 years ago
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