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Sever21 [200]
3 years ago
7

Decide if the following scenario involves a permutation or combination. Then find the number of possibilities. The student body

of 165 students wants to elect 3 representatives
Mathematics
1 answer:
Troyanec [42]3 years ago
6 0

Answer:

735,130.

Step-by-step explanation:

The order of election of the 3 representatives does not matter so it is a combination.

The number of possible combinations

= 165! / 162! 3!

=  (165 * 164 * 163) / (3*2*1)

= 735,130.

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krok68 [10]
Hello,

"T<span>he product of 8 and a number increased by 4" may be understood by 2 ways:
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2) it is the product which is increased.

1) 8*(y+4) =8y+32

2) (8y)+4=8y+4

Seeing answers
:answer A: 8y+4

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6 0
3 years ago
Based on the given information, what can you conclude and why
Dmitry_Shevchenko [17]
Notice the point R
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8 0
3 years ago
Simplify 3*a*2*b<br> *=multiply
morpeh [17]

Answer:

3 × a × 2 × b = 3a × 2b

7 0
3 years ago
Which is the graph of f(c)=1/4(4)^x?
Ronch [10]

Answer: The graph shown

Step-by-step explanation:

Another graph of the function is attached in this answer.

4 0
1 year ago
Jared is going to plant 20 small plants around the edge of a circular garden that is 8 feet in diameter. If he spaces the plants
Hatshy [7]

Answer:

The space between the plants is approximately 1.26ft

Step-by-step explanation:

Given

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Calculating the circumference....

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r = ½ * 8ft

r = 4ft

So,

Circumference = 2π * 4

Circumference = 8π ft

Given that the plants will be spaced evenly.

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Distance = 8π/20

Distance = 0.4π ft.

Solving further to get actual distance (take π as 22/7)

Distance = 0.4 * 22/7

Distance = 8.8/7

Distance = 1.2571428571 ft

Distance = 1.26ft (Approximated)

Hence, the space between the plants is approximately 1.26ft

3 0
3 years ago
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