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iogann1982 [59]
3 years ago
6

need some help with geo, could you explain how to do it as well so i know next time not needed but helpful

Mathematics
1 answer:
Setler [38]3 years ago
5 0
You can do this by finding the lengths of RT , RS and ST using the distance formula

RT = sqrt ((0- -5)^2  + (4 - -6)^2)
      = sqrt (5^2 + 10^2)  = sqrt 125

RS =  sqrt ((-3- -5)^2 +  (-2 - -6)^2))
       = sqrt  ( 2^2 + 4^2)  = sqrt 20

ST  = sqrt 125 - sqrt 20

RS / ST  = sqrt 20 / (sqrt 125-sqrt 20)

so the ratio RS:ST = 2:3

Its B
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A rectangle has a length of 1.5abc and a width of 10abc find the area of the rectangle
Vikentia [17]

Answer:

A =  15 a²b²c² square units

Step-by-step explanation:

Area of a rectangle = LW

                    A = (1.5abc)(10abc)

                    A =  15 a²b²c² square units

5 0
2 years ago
In triangle XYZ. the measurements of angle X and angle Y are 45° Which is the longest side of the triangle
ipn [44]

Answer:

the side XY

Step-by-step explanation:

we know 2 angles in a triangle. but are 45 degrees.

that means the third angle Z is 180-45-45 = 90 degrees.

the side opposite of the largest angle is the longest side.

opposite of Z is the side XY.

6 0
3 years ago
Can you help me with this thank you
Sveta_85 [38]
The correct answer is points
8 0
3 years ago
-91=13n How would you work out this math problem
Igoryamba

Answer:

n=-7

Step-by-step explanation:

For this you can do the inverse of division which is division. So Divide -91 and 13. Which is -7.

7 0
3 years ago
Read 2 more answers
WILL GIVE BRAINLIEST
Papessa [141]
<span>the particle's initial position is at t=0, x = 0 - 0 + 4 = 4m

velocity is rate of change of displacement = dx/dt = d(t^3 - 9t^2 +4)/dt
= 3t^2 - 18t

acceleration is rate of change of velocity = d(3t^2 -18t)/dt
= 6t - 18

</span><span>the particle is stationary when velocity = 0, so 3t^2 - 18t =0
</span>3t*(t - 6) = 0
t = 0 or t = 6s

acceleration = 6t - 18 = 0
t = 3s
at t = 3s, velocity = 3(3^2) -18*3 = -27m/s
displacement = 3^3 - 9*3^2 +4 = -50m


6 0
3 years ago
Read 2 more answers
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