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3 years ago

Can someone please anwser

1 answer:

7 0

Since all three equations are equal, you take 15 x 20, which =300, once again because all of the equations are equal, take 300 and divide it by 5, that will give you your first question mark.{you should have gotten 60.} To find the second one, you are going to apply the same concept, Take 300 and divide it by 6, giving you your second question mark. {you should have gotten 50}...
P.S.: {hope I helped} :)

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GUYS PLEASE HELP HELPING ME GIVES U 50 POINTS PLEASE HELP ME Y = 1/1 x + 1

Semenov [28]

Is it a fraction? Or what

6 0

3 years ago

Read 2 more answers

Julia is taking a test with multiple choice and true/false question the test has twentg question altogether . julia gets five po

Sonbull [250]

X=number of corect
y=number of incorrect
5 points for each correct so 5x
-1 point for each incorrect so -y

5x-y=76
solve for x and y

I like putting it into slope intercep tofrm which is y=mx+b
add y to both sides
5x=76+y
subtract 76 from both sides
5x-75=y
y=5x-76

subsitute values for x and get values for y
remember, that julia cannot answer a negative number of incorrect questions so y must be greater than or equal to 0

so solve for minimum
0<5x-76
add 76 to both sides
76<5x
divide by 5
15.2<x
you cannot answer a fraction of a correct quesiton so round up
16 is the minumum number of queswtions correctlyh answered

so
x>16

subsitute 16 for x
y=5(16)-76
y=80-76
y=4

as we subsitute more numbers over 16, we get these points
so (x,y)
(16,4)
(17,9)
(18,14)
(19,19)
(20,24)
(21,29)
(22,34)
(23,39)
x=correct answer
y=wrong answers

5 0

3 years ago

Could I get help on some algebra? I need the explanation to know how to do it. +45 points

Fiesta28 [93]

Answer:

Step-by-step explanation:

A is right, D is right because they are on the outside and on different sides, B is actually right since they are on the inside and on different sides, so that leaves c, so this has to be the wrong one because they are not both interior since 5 is on the outside and 6 is inside even if they are both on the same side

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3 years ago

Which expressions are equivalent to the given expression

lora16 [44]

Answer:

Step-by-step explanation:

5 0

3 years ago

A data mining routine has been applied to a transaction dataset and has classified 88 records as fraudulent (30 correctly so) an

chubhunter [2.5K]

Answer:

The classification matrix is attached below

Part a

The classification error rate for the records those are truly fraudulent is 65.91%.

Part b

The classification error rate for records that are truly non-fraudulent is 96.64%

Step-by-step explanation:

The classification matrix is obtained as shown below:

The transaction dataset has 30 fraudulent correctly classified records out of 88 records, that is, 30 records are correctly predicted given that an instance is negative.

Also, there would be 88 - 30 = 58 non-fraudulent incorrectly classified records, that is, 58 records are incorrectly predicted given that an instance is positive.

The transaction dataset has 920 non-fraudulent correctly classified records out of 952 records, that is, 920 records are correctly predicted given that an instance is positive.

Also, there would be 952 - 920 = 32 fraudulent incorrectly classified records, that is, 32 records incorrectly predicted given that an instance is negative.

That is,

Predicted value

Active value Fraudulent Non-fraudulent

Fraudlent 30 58

non-fraudulent 32 920

The classification matrix is obtained by using the information related to the transaction data, which is classified into fraudulent records and non-fraudulent records.

The error rate is obtained as shown below:

The error rate is obtained by taking the ratio of $\left( {b + c} \right)(b+c)$ and the total number of records.

The classification matrix is, shown above

The total number of records is, $30 + 58 + 32 + 920 = 1,040$

The error rate is,

$\begin{array}{c}\\{\rm{Error}}\,{\rm{rate}} = \frac{{b + c}}{{{\rm{Total}}}}\\\\ = \frac{{58 + 32}}{{1,040}}\\\\ = \frac{{90}}{{1,040}}\\\\ = 0.0865\\\end{array}$

The percentage is $0.0865 \times 100 = 8.65$

(a)

The classification error rate for the records those are truly fraudulent is obtained by taking the rate ratio of b and $\left( {a + b} \right)(a+b)$ .

The classification error rate for the records those are truly fraudulent is obtained as shown below:

The classification matrix is, shown above and in the attachment

The error rate for truly fraudulent is,

$\begin{array}{c}\\FP = \frac{b}{{a + b}}\\\\ = \frac{{58}}{{30 + 58}}\\\\ = \frac{{58}}{{88}}\\\\ = 0.6591\\\end{array}$

The percentage is, $0.6591 \times 100 = 65.91$

(b)

The classification error rate for records that are truly non-fraudulent is obtained by taking the ratio of d and $\left( {c + d} \right)(c+d)$ .

The classification error rate for records that are truly non-fraudulent is obtained as shown below:

The classification matrix is, shown in the attachment

The error rate for truly non-fraudulent is,

$\begin{array}{c}\\TP = \frac{d}{{c + d}}\\\\ = \frac{{920}}{{32 + 920}}\\\\ = \frac{{920}}{{952}}\\\\ = 0.9664\\\end{array}$

The percentage is, $0.9664 \times 100 = 96.64$

8 0

3 years ago