I think the answer is 7/5.
I would add 1/6 to 3/6 2/3 is equal to 4/6 to 1/6 plus 3/6 is 4/6
Answer:
60%
Step-by-step explanation:
We have that there are 6 75-W bulbs, that is to say these are the favorable cases. The total cases would be the sum of all the bulbs that would be:
4 + 5 + 6 = 15
Therefore the probability of at least 1 75-W bulbs is:
6/15 = 0.4
Now we must find the probability of at least 2 75-W bulbs, which is like this:
P (examine at least two 75-W bulbs) = 1 - P (examine at most one 75-W bulbs)
Replacing:
P (examine at least two 75-W bulbs) = 1 - 0.4 = 0.6
It means that the probability of least two 75-W bulbs is 60%
Answer:
I think it's uhm twelve I'm not 100% sure though
