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gladu [14]
3 years ago
11

HELP ME PLEASE!!!!!!!!

Mathematics
1 answer:
ale4655 [162]3 years ago
4 0
I think this is how you do it

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How many 5-digit numbers can be formed using the digits 0, 1, 2, 3, 4, 5, 6, if repetition of digits is not allowed? a.119 b.16,
Sergeeva-Olga [200]
Answer:
c. 2520

Explanation:
Repetition is not allowed, therefore:
1st digit can be any of the given 7 numbers
2nd digit can be any of the remaining 6 numbers
3rd digit can be any of the remaining 5 numbers
4th digit can be any of the remaining 4 numbers
5th digit can be any of the remaining 3 numbers
This means that:
number of possible combinations = 7 * 6 * 5 * 4 * 3 = 2520 numbers

Hope this helps :)
5 0
3 years ago
Can someone give me the answer to this please? :)
Ber [7]
I believe the answer is c
6 0
3 years ago
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How many extraneous solutions are there ?
vfiekz [6]
2 is your correct answer
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Please answer kxjjsjnsssmsmmxmdmxmxmmxx​
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4 0
3 years ago
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Which set represents the same relation as the table below?
erik [133]

Answer:

A) { (0, 5), (4, 2), (6, 9), (9, 10)}

Step-by-step explanation:

From the table values, we can write the relation in coordinate form (x, f(x)).

The first value is x and the second value is f(x) in the coordinate.

Let's write the coordinates from the given table.

(0, 5), (4, 2), (6, 9), (9, 10)

Let's write the above coordinates in set form.

{ (0, 5), (4, 2), (6, 9), (9, 10)}

The set A is same relation as the given table.

Answer: A) { (0, 5), (4, 2), (6, 9), (9, 10)}

Hope you will understand the concept.

Thank you.

5 0
3 years ago
Read 2 more answers
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