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gladu [14]
2 years ago
11

HELP ME PLEASE!!!!!!!!

Mathematics
1 answer:
ale4655 [162]2 years ago
4 0
I think this is how you do it

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GIVING BRAINLIEST FOR BEST ANSWER!<br> Write a story that could represent this math problem.
STatiana [176]

Answer:

I have zero clue what the hell this is supposed to be

Step-by-step explanation:

3 0
2 years ago
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Solve for x<br> (2x - 3)(x - 2) = 0
Zinaida [17]

Answer:

?

Step-by-step explanation:

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Alyssa goes out for dinner, and the price of her meal is $18. The sales tax on the meal is 6%, and she also wants to leave a 20%
Oksana_A [137]

Answer:

$22.68

Step-by-step explanation:

Meal Price =$18

Sales tax =6%

Tip = 20%

Total Price of the Meal =$18 + (6% of 18)+ (20% of 18)

=$18 + (0.06 X 18)+ (0.2 X 18)

=18+1.08+3.6

=$22.68

The total price of Alyssa's meal is $22.68.

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3 years ago
What is 6.5 multiplied by 0.2?
Angelina_Jolie [31]
The answer to this is 1.3
5 0
3 years ago
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A trucking firm suspects that the mean life of a certain tire. it uses is less than 33,000 miles. To check the claim, the firm r
Mice21 [21]

Answer:

We accept the alternate hypothesis. We conclude that the mean lifetime of tires is  is less than 33,000 miles.

Step-by-step explanation:

We are given the following in the question:  

Population mean, μ = 33,000 miles

Sample mean, \bar{x} =  32, 450 miles

Sample size, n = 18

Alpha, α = 0.05

Sample standard deviation, s = 1200 miles

a) First, we design the null and the alternate hypothesis

H_{0}: \mu = 33000\text{ miles}\\H_A: \mu < 33000\text{ miles}

b) Level of significance:

\alpha = 0.05

c) We use One-tailed t test to perform this hypothesis.

d) Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} } Putting all the values, we have

t_{stat} = \displaystyle\frac{32450 - 33000}{\frac{1200}{\sqrt{18}} } = -1.9445

Now, t_{critical} \text{ at 0.05 level of significance, 17 degree of freedom } = -1.7396

Rejection area:

t < -1.7396

Since,                  

t_{stat} < t_{critical}

e) We fail to accept the null hypothesis and reject it as the calculated value of t lies in the rejection area.

f) We accept the alternate hypothesis. We conclude that the mean lifetime of tires is  is less than 33,000 miles.

3 0
3 years ago
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