Answer Whatever One you want! (Although all would be nice) In return a thanks!!!

Taleen has 8 stamps in her collection, and she decides that each month she will add 3 stamps to her collection.

AnnZ [28]

Answer:

1) The rate of change represents the number of stamps she adds each month.

2) The rate of change is 3 stamps per month

3) How many stamps she has in her collection before she starts adding 3 every month.

4) 8 stamps.

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

What is the value of x in the equation 4x + 8y =40 when y =0.8

Neko [114]

Y = 0.8

4x + 8y = 40

4x + 8*(0.8) = 40

4x + 6.4 = 40

4x = 40 - 6.4

4x = 33.6

x = 8.4

7 0

2 years ago

Advertising expenses are a significant component of the cost of goods sold. Listed below is a frequency distribution showing the

Alexxandr [17]

Answer:

Step-by-step explanation:

The table can be computed as:

Advertising Expenses ($ million) Number of companies

25 up to 35 4

35 up to 45 19

45 up to 55 27

55 up to 65 16

65 up to 75 9

TOTAL 75

Let's find the probabilities first:

$P(25 - 35) = P \Big(\dfrac{25-50.93}{10.80}$

For 35 up to 45

$P(35 - 45) = P \Big(\dfrac{35-50.93}{10.80}$

For 45 up to 55

$P(45 - 55) = P \Big(\dfrac{45-50.93}{10.80}$

For 55 up to 65

$P(55 - 65) = P \Big(\dfrac{55-50.93}{10.80}$

For 65 up to 75

$P(65 - 75) = P \Big(\dfrac{65-50.93}{10.80}$

Chi-Square Table can be computed as follows:

Expense No of Probabilities(P) Expe $(O-E)^2$ $\dfrac{(O-E)^2}{E}$

compa cted E (n*p)

nies (O)

25-35 4 0.0612 75*0.0612 = 4.59 0.3481 0.0758

35-45 19 0.2218 75*0.2218 = 16.635 5.5932 0.3362

45-55 27 0.3568 75*0.3568 = 26.76 0.0576 0.021

55-65 16 0.2552 75*0.2552 = 19.14 9.8596 0.5151

65-75 9 0.0839 75*0.0839 = 6.2925 7.331 1.1650

$\sum \dfrac{(O-E)^2}{E}= 2.0492$

Using the Chi-square formula:

$X^2 = \dfrac{(O-E)^2}{E} \\ \\ Chi-square \ X^2 = 2.0942$

Null hypothesis:

$H_o: \text{The population of advertising expenses follows a normal distribution}$

Alternative hypothesis:

$H_a: \text{The population of advertising expenses does not follows a normal distribution}$

Assume that:

$\alpha = 0.02$

degree of freedom:

= n-1

= 5 -1

= 4

Critical value from $X^2 = 11.667$

Decision rule: To reject $H_o \ if \ X^2$ test statistics is greater than $X^2$ tabulated.

Conclusion: Since $X^2 = 2.0942$ is less than critical value 11.667. Then we fail to reject $H_o$

6 0

2 years ago

If a person walks 2.4 miles in 1.5 hours, how far can he walk in 3 hours

rusak2 [61]

since 1.5 is half of 3.0 all ouj havr t o do is multiply by 2 2.4*2=4.8 answer

7 0

2 years ago

The width rectangle is 43 centimeters The perimeter is at least 198 cm let the length of the rectangle be /.

AnnyKZ [126]

Answer:

198/43

Step-by-step explanation:

4 0

2 years ago