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emmainna [20.7K]
3 years ago
9

Another important mode, XTS-AES, has been standardized by the __________ Security in Storage Working Group. a. IEEE b. ITIL c. N

IST d. ISO
Computers and Technology
2 answers:
Archy [21]3 years ago
8 0

Answer:

a. IEEE

Explanation:

The organization with the acronym 'IEEE' is commonly known as the Institute of Electrical and Electronics Engineer. The organization is responsible for the standardization and implementation of various important modes such as the XTS-AES. This is widely used for data encryption and it is a major part of the AES algorithm.

lara31 [8.8K]3 years ago
4 0

Answer:

a. IEEE

Explanation:

Another important mode, XTS-AES, has been standardized by the<u> IEEE</u> Security in Storage Working Group

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In the context of organizational decisions at the tactical management level, _____ decisions are often used in resolving conflic
natali 33 [55]

Answer:

b. structured

Explanation:

Based on the information being described within the question it can be said that the type of decisions being mentioned are known as structured decisions. These are decisions which have various processes in place in order to handle a certain situation. Usually due to the problem having occurred countless times and are predictable.

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3 years ago
An executable file that was determined to be infected with a virus was terminated from the running processes list. However, afte
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Mostly Trojan will has multiple version and I love u virus extra.

<u>Explanation:</u>

As first step workstation or desktop or laptop to scanned for virus and if any virus or malware found then it should be removed first. Operating system should be updated with latest patch, virus signature also be updated once again executed founded by virus infected.

Better to copy new exes and place in the same folder and try to execute again. If still the problem persists download antivirus software such as Norton, bit defender, Kaspersky etc. executable files affected by 15-20 viruses

8 0
3 years ago
Annie needs to provide a form field that will allow users to select from a predefined list of options but without the ability to
Lana71 [14]

Answer:

Drop down list

Explanation:

You have not listed what the possible answers are, however a drop down list would be an option to accomplish this.

8 0
3 years ago
Special numeric has three digits and holds a property that it is exactly equal to summation of cubes from each digit. For exampl
Vera_Pavlovna [14]

Answer:

The following code is written in C programming language:

#include <stdio.h>     //header file

 

int main()       //main method

{

   int n, t, digit1, digit2, digit3;      // set integer variables

    // print message

   printf("Print all Special integer numbers between 100 and 999:\n");

   n = 100;      //initialize value in variable "n"    

   while (n <= 999)      //set while loop

   {

       digit1 = n - ((n / 10) * 10);

       digit2 = (n / 10) - ((n / 100) * 10);

       digit3 = (n / 100) - ((n / 1000) * 10);

       t = (digit1 * digit1 * digit1) + (digit2 * digit2 * digit2) + (digit3 * digit3 * digit3);

       if (t == n)      //set if statement

       {

           printf("\n Special integer number is: %d", t);     //print an output

       }

       n++;

   }

}

Output:

Print all Special integer numbers between 100 and 999:

Special integer number is: 153

Special integer number is: 370

Special integer number is: 371

Special integer number is: 407

Explanation:

Here, we set the header file "stdio.h".

Then, we define integer type "main()" function.

Then, we set five integer type variable "n", "t", "digit1", "digit2", "digit3".

Then, we the print message by print() method and initialize a value to variable "n" to 100.

Then, we set the while loop which starts from 100 and stops at 999 and if the condition is true than code inside the loop is execute either loop is terminated.

Then, we set the if statement and pass the condition, if the condition is true the output would be print either if the condition is false the if statement is terminated.

8 0
3 years ago
In this chapter, you saw an example of how to write an algorithm that determines whether a number is even or odd. Write a progra
vagabundo [1.1K]

Answer:

// Program is written in Java Programming Language

// Comments are used for explanatory purpose

// Program starts here

public class RandomOddEve {

/** Main Method */

public static void main(String[] args) {

int[] nums = new int[100]; // Declare an array of 100 integers

// Store the counts of 100 random numbers

for (int i = 1; i <= 100; i++) {

nums[(int)(Math.random() * 10)]++;

}

int odd = 0, even = 0; // declare even and odd variables to 0, respectively

// Both variables will serve a counters

// Check for odd and even numbers

for(int I = 0; I<100; I++)

{

if (nums[I]%2 == 0) {// Even number.

even++;

}

else // Odd number.

{

odd++;

}

}

//.Print Results

System.out.print("Odd number = "+odd);

System.out.print("Even number = "+even);

}

8 0
3 years ago
Read 2 more answers
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