Answer:
Control bus
Explanation:
A control bus is a PC bus that is utilized by the CPU to speak with gadgets that are contained inside the PC. This happens through physical associations, for example, links or printed circuits.
The CPU transmits an assortment of control sign to parts and gadgets to transmit control sign to the CPU utilizing the control bus. One of the principle targets of a transport is to limit the lines that are required for communication
An individual bus licenses communication between gadgets utilizing one information channel. The control transport is bidirectional and helps the CPU in synchronizing control sign to inside gadgets and outer segments. It is included interfere with lines, byte empower lines, read/compose sign and status lines.
Answer:
import java.util.Scanner;
public class Speed{
int speed;
public Speed(int speed){
this.speed = speed;
}
public void checkSpeed(){
if(speed >= 24 || speed <= 56){
System.out.println("Speed is normal");
}
else
System.out.println("Speed is abnormal");
}
public static void main(String...args){
Scanner input = new Scanner(System.in);
int userSpeed = 0;
System.out.println("Enter a speed: ");
userSpeed = input.nextInt();
Speed obj1 = new Speed(userSpeed)
obj1.checkSpeed();
}
Explanation:
It is A, the theme is the subject.
Answer:
"Web designer" is the appropriate answer.
Explanation:
- If we follow the market pattern, the number of purchases made by online shopping will continue to rise from 2002 to 2018 as well as the times to obtain no indication of slowing or stopping.
- Because of the same, web designers are expected to have the greatest increase in jobs, as it is very important to customize the website so that online customers can appear more interactive.
So that the above is the correct answer.
Answer:
Explanation:
The minimum depth occurs for the path that always takes the smaller portion of the
split, i.e., the nodes that takes α proportion of work from the parent node. The first
node in the path(after the root) gets α proportion of the work(the size of data
processed by this node is αn), the second one get (2)
so on. The recursion bottoms
out when the size of data becomes 1. Assume the recursion ends at level h, we have
(ℎ) = 1
h = log 1/ = lg(1/)/ lg = − lg / lg
Maximum depth m is similar with minimum depth
(1 − )() = 1
m = log1− 1/ = lg(1/)/ lg(1 − ) = − lg / lg(1 − )
