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olga55 [171]
3 years ago
13

What is the degree of 5x^3+3x^2-4x+1 3 4 5 6

Mathematics
1 answer:
sergeinik [125]3 years ago
3 0
The degree is 3 because that is the highest exponent in the equation
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Help please
bixtya [17]

Answer:

dasd

Step-by-step explanation:

sdas

7 0
2 years ago
A number equivalent to 63.24
tankabanditka [31]
63.24 is equivalent to 63.240.
7 0
3 years ago
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verifica care dintre urmatoarele numere sunt cuburi perfecte:2 la puterea a 8, 27, 64, 5 la puterea 48, si 7 la puterea 225
4vir4ik [10]

Answer:

Step-by-step explanation:

8,27,64,548, it is 355

6 0
2 years ago
After an antibiotic tablet is taken, the concentration of the antibiotic in the bloodstream is modelled by the function C(t)=8(e
Alexxx [7]

Answer:

the maximum concentration of the antibiotic during the first 12 hours is 1.185 \mu g/mL at t= 2 hours.

Step-by-step explanation:

We are given the following information:

After an antibiotic tablet is taken, the concentration of the antibiotic in the bloodstream is modeled by the function where the time t is measured in hours and C is measured in \mu g/mL

C(t) = 8(e^{(-0.4t)}-e^{(-0.6t)})

Thus, we are given the time interval [0,12] for t.

  • We can apply the first derivative test, to know the absolute maximum value because we have a closed interval for t.
  • The first derivative test focusing on a particular point. If the function switches or changes from increasing to decreasing at the point, then the function will achieve a highest value at that point.

First, we differentiate C(t) with respect to t, to get,

\frac{d(C(t))}{dt} = 8(-0.4e^{(-0.4t)}+ 0.6e^{(-0.6t)})

Equating the first derivative to zero, we get,

\frac{d(C(t))}{dt} = 0\\\\8(-0.4e^{(-0.4t)}+ 0.6e^{(-0.6t)}) = 0

Solving, we get,

8(-0.4e^{(-0.4t)}+ 0.6e^{(-0.6t)}) = 0\\\displaystyle\frac{e^{-0.4}}{e^{-0.6}} = \frac{0.6}{0.4}\\\\e^{0.2t} = 1.5\\\\t = \frac{ln(1.5)}{0.2}\\\\t \approx 2

At t = 0

C(0) = 8(e^{(0)}-e^{(0)}) = 0

At t = 2

C(2) = 8(e^{(-0.8)}-e^{(-1.2)}) = 1.185

At t = 12

C(12) = 8(e^{(-4.8)}-e^{(-7.2)}) = 0.059

Thus, the maximum concentration of the antibiotic during the first 12 hours is 1.185 \mu g/mL at t= 2 hours.

4 0
2 years ago
The sum of 3 consecutive integers is 78. What is the integer closest to zero?
vova2212 [387]

Answer:

25

Step-by-step explanation:

Let n be the first integer.

Then the second integer will be (n + 1).

And the third will be (n + 2).

The sum is 78. Therefore:

n+(n+1)+(n+2)+78

Solve for n. Combine like terms:

3n+3=78

So:

3n=75

Therefore:

n=25

Therefore, the first integer is 25.

So our sequene is 25, 26, and 27.

The integer closest to zero will thus be 25.

5 0
2 years ago
Read 2 more answers
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