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3 years ago

Evaluate: 54 - 75 + 81 - (-27) + 53

Mathematics

2 answers:

olga55 [171]3 years ago

7 0

Answer:

140.

Step-by-step explanation:

PEMDAS.

Since there isn't any problems that aren't adding, we can just do it step by step.

54 - 75.

-21.

Add 81.

60.

Subtract -27.

87.

Add 53.

140.

Brainiest?

Kamila [148]3 years ago

4 0

Answer:

140

Step-by-step explanation:

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A set of data with 100 observati removed, what is the mean of the new data se of 267 There are six outliers in the data set, whi

Andreas93 [3]

Answer:

<u>the mean-average of the data without the outliers is 22572/94 = 240.12766 correct to four digits.</u>

Step-by-step explanation:

If the six outliers are removed, what is the mean average of the remaining data... is ASSUMED what the question was supposed to ask. I'll go out on a limb here, because there really isn't much else you can calculate with just

this much data anyways. I refer to the mean or average as the mean-average....just sayin'

Mean-Average = total/count , which means the total = count * mean-average.

Well, the data containing the outliers has a mean-average of 267 and a count of 100 statistics as given in the problem. So the total of all of the data including the outliers is 26700.

Likewise, the six outliers have a mean-average of 688 as given in the problem.

So the total of the outliers is 688 * 6 = 4128.

As a result, the total of the 94 statistics when the six outliers are rejected is 26700-4128=22572.

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3 years ago

Write the congruence

Andreas93 [3]

Hi I wanna was a good morning

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3 years ago

Calculus help ASAP!!!

anastassius [24]

Let $c\in(0,\infty)$ . Then the definite integral can be split up at $t=c$ so that

$\displaystyle F(x)=\int_{t=2x}^{t=5x}\frac{\mathrm dt}t$
$\displaystyle=\int_{t=2x}^{t=c}\frac{\mathrm dt}t+\int_{t=c}^{t=5x}\frac{\mathrm dt}t$
$\displaystyle=-\int_{t=c}^{t=2x}\frac{\mathrm dt}t+\int_{t=c}^{t=5x}\frac{\mathrm dt}t$

Now take the derivative. By the fundamental theorem of calculus, you have

$\displaystyle\frac{\mathrm dF}{\mathrm dx}=\frac{\mathrm d}{\mathrm dx}\left[\int_{t=c}^{t=5x}\frac{\mathrm dt}t-\int_{t=c}^{t=2x}\frac{\mathrm dt}t\right]$
$=\displaystyle\frac1{5x}\dfrac{\mathrm d}{\mathrm dx}[5x]-\frac1{2x}\dfrac{\mathrm d}{\mathrm dx}[2x]$
$=\dfrac5{5x}-\dfrac2{2x}$
$=\dfrac1x-\dfrac1x$
$=0$

Then integrating with respect to $x$ , we recover $F(x)$ and find that

$\displaystyle\int\dfrac{\mathrm dF}{\mathrm dx}\,\mathrm dx=\int0\,\mathrm dx$
$F(x)=C$

where $C$ is an arbitrary constant.