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3 years ago

Explain how to multiply the complex #'s (3+2i)(4-i)

1 answer:

8 0

Multiply the numbers like you multiply binomials.
Multiply every term of the first binomial by every term of the second binomial.
Then combine like terms, and remember that i^2 = -1.

(3 + 2i)(4 - i) =

= 12 - 3i + 8i - 2i^2

= 12 + 5i + 2

= 14 + 5i

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3 years ago

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Please help.........

Alex

Answer:

- $\frac{61}{11}$

Step-by-step explanation:

$\frac{x}{y}$ = $\frac{5}{6}$ ( cross- multiply )

6x = 5y ( divide both sides by 6 )

x = $\frac{5}{6}$ y

Then

$\frac{5x+6y}{5x-6y}$ ← substitute x = $\frac{5}{6}$ y into the expression

= $\frac{\frac{25}{6}y+6y }{\frac{25}{6}y-6y }$

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3 years ago

3/8 x 2/6 x 4/8 x 5/12

Hatshy [7]

Answer:

$\frac{5}{192}$

Step-by-step explanation:

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