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3 years ago

When a figure is translated, reflected, or rotated, what's the same about the original

Mathematics

2 answers:

GuDViN [60]3 years ago

8 0

Answer:

The figures are congruent.

Step-by-step explanation:

The figures are same shape and size, but we are allowed to flip, slide or turn. In this example the shapes are congruent (you only need to flip one over and move it a little). Angles are congruent when they are the same size (in degrees or radians).

navik [9.2K]3 years ago

5 0

Answer:

Its angles and its sides remain the same! Also its shape and size. The difference is the figures location/position. Hope this helps :)

Step-by-step explanation:

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2 divided by negative 1/5

oksian1 [2.3K]

Answer: 10

you have to find a common denominator between two and five which is 10. therefore making the number 2 into the fraction 20/10 and finding the common denominator of 1/5 makes it now 2/10. now divide 20 by 2 which gets you 10. and dividing 10 by 10 gets you. therefore making the new fraction 10/1 which is equal to 10. :)

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3 years ago

Graph the following equation:<br><br> y=4x-3

Yuki888 [10]

Do you have a better graph I could see

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2 years ago

A boat can travel 456 miles on 114<br> gallons of gasoline. How far can it<br> travel on 67 gallons?

Ede4ka [16]

Answer:

268 miles i think

Step-by-step explanation:

if 456=114 gallons

456/114=4

so 4 miles per gallon

and then

4*67=268

Hope this helps: )

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3 years ago

How to find the distance between a focous and a directrix

zlopas [31]

The absolute value of p is the distance between the vertex and the focus and the distance between the vertex and the directrix. (The sign on p tells me which way the parabola faces.) Since the focus and directrix are two units apart, then this distance has to be one unit, so.

7 0

4 years ago

Webassign find the area of the region bounded by the parabola y = x2, the tangent line to this parabola at the point (6, 36), an

Dvinal [7]

First find the tangent line

dy/dx=2x
at x=6, the slope is 2(6)=12
so
use point slope form
y-y1=m(x-x1)
point is (6,36)
so
y-36=12(x-6)
y-36=12x-72
y=12x-36

alright, so we know they intersect at x=6
and y=12x-36 is below y=x^2

so we do $\int\limits^6_0 {x^2} \, dx - \int\limits^6_0 {12x-36} \, dx = \int\limits^6_0 {x^2-(12x-36)} \, dx = \int\limits^6_0 {x^2-12x+36} \, dx =$
$[\frac{x^3}{3}-6x^2+36x]\limits^6_0=(\frac{6^3}{3}-6(6)^2+36(6))-(0)=\frac{216}{3}-216+216=$ $72+0=72$

the area under the curve bounded by the lines and the x axis is 72 square units

4 0

3 years ago