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2 years ago

When a figure is translated, reflected, or rotated, what's the same about the original

Mathematics

2 answers:

GuDViN [60]2 years ago

8 0

Answer:

The figures are congruent.

Step-by-step explanation:

The figures are same shape and size, but we are allowed to flip, slide or turn. In this example the shapes are congruent (you only need to flip one over and move it a little). Angles are congruent when they are the same size (in degrees or radians).

navik [9.2K]2 years ago

5 0

Answer:

Its angles and its sides remain the same! Also its shape and size. The difference is the figures location/position. Hope this helps :)

Step-by-step explanation:

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Pls answer time sensitive

vovikov84 [41]

Answer:

i would say that the rocket was in the air for 8 seconds and the highest it went in the air was 48

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Lin has 4 pinecones and some acorns.

frozen [14]

Answer:

Lin has 11 acorns ⇒ answer D

He subtract 4 from 7 instead of add 4 to 7

Step-by-step explanation:

- Lin has 4 pinecones and some acorns

- She has 7 fewer pinecones than acorns

- The meaning of 7 fewer pinecones than acorns is the number of the

pinecones is less than the number of acorns by 7

∵ She has 4 pinecones

∵ She has 7 fewer pinecones than acorns

- The number of pine cones is less than the number of acorns by 7

∴ 4 = number of acorns - 7

- Add 7 to both sides

∴ 11 = number of acorns

* Lin has 11 acorns

- Tom choose answer A which is 3

- He made a mistake in the equation

- He put ⇒ number of the acorns = 7 - 4 not 7 + 4

∴ number of acorns = 3

* He subtract 4 from 7 instead of add 4 to 7

8 0

3 years ago

Write a linear function f with the values f(2)=4 and f(−7)=9. A function is f(x)=

ale4655 [162]

Answer:

f(x) = -5/9 x + 5 1/9

Step-by-step explanation:

f(2)=4 and f(−7)=9 means the line pass through (2,4) and (- 7,9)

f(x) = mx + b

m = (y-y') / (x-x') = (9 - 4) / (- 7 - 2) = - 5/9

for (2,4) : b = f(x) - mx = y - mx = 4 - (- 5/9) x 2 = 4 + 10/9 = 46/9 = 5 1/9

f(x) = -5/9 x + 5 1/9

check for (-7, 9) f(-7) = (-5/9) * (-7) + 5 1/9 = 35/9 + 46/9 = 81/9 = 9

5 0

3 years ago

A metal cylinder can with an open top and closed bottom is to have volume 4 cubic feet. Approximate the dimensions that require

Aleksandr-060686 [28]

Answer:

$r\approx 1.084\ feet$

$h\approx 1.084\ feet$

$\displaystyle A=11.07\ ft^2$

Step-by-step explanation:

Optimizing With Derivatives

The procedure to optimize a function (find its maximum or minimum) consists in :

Produce a function which depends on only one variable
Compute the first derivative and set it equal to 0
Find the values for the variable, called critical points
Compute the second derivative
Evaluate the second derivative in the critical points. If it results positive, the critical point is a minimum, if it's negative, the critical point is a maximum

We know a cylinder has a volume of 4 $ft^3$ . The volume of a cylinder is given by

$\displaystyle V=\pi r^2h$

Equating it to 4

$\displaystyle \pi r^2h=4$

Let's solve for h

$\displaystyle h=\frac{4}{\pi r^2}$

A cylinder with an open-top has only one circle as the shape of the lid and has a lateral area computed as a rectangle of height h and base equal to the length of a circle. Thus, the total area of the material to make the cylinder is

$\displaystyle A=\pi r^2+2\pi rh$

Replacing the formula of h

$\displaystyle A=\pi r^2+2\pi r \left (\frac{4}{\pi r^2}\right )$

Simplifying

$\displaystyle A=\pi r^2+\frac{8}{r}$

We have the function of the area in terms of one variable. Now we compute the first derivative and equal it to zero

$\displaystyle A'=2\pi r-\frac{8}{r^2}=0$

Rearranging

$\displaystyle 2\pi r=\frac{8}{r^2}$

Solving for r

$\displaystyle r^3=\frac{4}{\pi }$

$\displaystyle r=\sqrt[3]{\frac{4}{\pi }}\approx 1.084\ feet$

Computing h

$\displaystyle h=\frac{4}{\pi \ r^2}\approx 1.084\ feet$

We can see the height and the radius are of the same size. We check if the critical point is a maximum or a minimum by computing the second derivative

$\displaystyle A''=2\pi+\frac{16}{r^3}$